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LuckyWell [14K]
3 years ago
5

the distance a spring will stretch varies directly with how much weight is attached to the spring. If a spring stretches 11 inch

es with 75 pounds attached, how far will it stretch with 65 attached? Round to the nearest tenth of an inch.
Physics
1 answer:
Paha777 [63]3 years ago
4 0
Direct variation involves ration and proportions, so 

you need to set up the proportion:

<span>11 / 75 = x / 65
 
Cross multiplying:

75x = 11*65

x = (11*65)/75

Solving, we get x = 9.533, </span>

<span>which rounds off to 9.5

Therefore, the spring will stretch up to 9.5 inches with 65 attached.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

</span>
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In a mixture of the gases oxygen and helium, which statement is valid:

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                                     E_k = 0.5*m*v_rms^2

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                                    E_k = 0.5*3*k*T

Hence, E_k is only the function of Temperature which we already established to remain constant at equilibrium.

                                   

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