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LuckyWell [14K]
3 years ago
5

the distance a spring will stretch varies directly with how much weight is attached to the spring. If a spring stretches 11 inch

es with 75 pounds attached, how far will it stretch with 65 attached? Round to the nearest tenth of an inch.
Physics
1 answer:
Paha777 [63]3 years ago
4 0
Direct variation involves ration and proportions, so 

you need to set up the proportion:

<span>11 / 75 = x / 65
 
Cross multiplying:

75x = 11*65

x = (11*65)/75

Solving, we get x = 9.533, </span>

<span>which rounds off to 9.5

Therefore, the spring will stretch up to 9.5 inches with 65 attached.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

</span>
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Why do the four outer planets have lower density than the four inner planets?
Marrrta [24]
Because the four outer planets are comprised of mostly gases give me a thanks or brainiest answer if this helps! 
4 0
3 years ago
in the circuit diagram even in suppose the resistor R1 R2 and R3 have the value of 5 ohm 10 ohm 30 ohm respectively which have b
Anuta_ua [19.1K]
<h3><u>Given</u> :</h3>

Three identical resistors of resistances 5Ω, 10Ω and 30Ω are connected with a battery of 12V.

<h3><u>To Find</u> :</h3>

We have to find current through the each resistor and equivalent resistance of circuit.

<h3><u>SoluTion</u> :</h3>

➝ Equivalent resistance of series connection is given by

  • <u>R = R1 + R2 + R3</u>

➝ We know that, Equal current flow through each resistor in series connection.

➝ As per ohm's law, Current flow through a conductor is directly proportional to the applied potential difference.

  • <u>V = IR</u>

◈ <u>Equivalent resistance</u> :

⇒ Req = R1 + R2 + R3

⇒ Req = 5 + 10 + 30

⇒ <u>Req = 45Ω</u>

◈ <u>Current flow in circuit</u> :

⇒ V = IReq

⇒ 12 = I × 45

⇒ <u>I = 0.27A</u>

፨ Therefore, 0.27A current will flow through each resistor.

5 0
3 years ago
If your mass is 63.7kg and standing 7.5m away from a boulder with a mass of 9750.6kg what is the gravitational force?
Anna11 [10]

Answer:

7.37 x 10^--7 N

Explanation:

Did it on A P E X

3 0
3 years ago
How to Answer questions 12 and 13
zubka84 [21]

12) The weight of the plane is 7.35\cdot 10^5 N

13) The lift provided by the wing is 7.35\cdot 10^5 N

Explanation:

12)

The weight of an object is equal to the force of gravity acting on the object. Near the Earth's surface, it can be calculated as

W=mg

where

W is the weight

m is the mass of the object

g is the acceleration of gravity

In this problem, we know that the mass of the plane is

m = 75 tonnes

Since 1 ton = 1000 kg, the mass in kg is

m = 75,000 kg

Also, the acceleration of gravity is

g=9.8 m/s^2

Therefore, the weight of the plane is:

W=(75,000)(9.8)=7.35\cdot 10^5 N

13)

We can solve this question by applying Newton's second law along the vertical direction of motion. In fact, the net force acting along the vertical direction must be equal to the product between the mass of the plane and the vertical acceleration:

\sum F_y = ma_y

where

\sum F_y is the net force in the y-direction

m is the mass of the plane

a_y is the acceleration in the y-direction

There are two forces acting in the vertical direction:

  • The lift L, acting upward
  • The weight W, acting  downward

So the vertical net force is

\sum F_y = L-W

And the equation becomes

L-W = ma_y

Also, we know that the plane is travelling in level flight, which means that the vertical acceleration is zero:

a_y = 0

Therefore, we get

L-W=0

And so the lift is

L=W=7.35\cdot 10^5 N

Learn more about  forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

4 0
3 years ago
A child is sliding a toy block (with mass = m) down a ramp. The coefficient of static friction between the block and the ramp is
tiny-mole [99]

Answer:

F=mg(sin(\theta )-0.25 cos(\theta ))

Explanation:

The free body diagram of the block on the slide is shown in the below figure

Since the block is in equilibrium we apply equations of statics to compute the necessary unknown forces

N is the reaction force between the block and the slide

For equilibrium along x-axis we have

\sum F_{x}=0\\\\mgsin(\theta )-\mu N-F=0\\\therefore F=mgsin(\theta)-\mu N......(\alpha )\\Similarly\\\sum F_{y}=0\\\\N-mgcos(\theta )=0\\\therefore N=mgcos(\theta ).......(\beta )\\\\

Using value of N from equation β in α we get value of force as

F=mg(sin(\theta )-\mu cos(\theta ))

Applying values we get

F=mg(sin(\theta )-0.25 cos(\theta ))

8 0
3 years ago
Read 2 more answers
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