the distance a spring will stretch varies directly with how much weight is attached to the spring. If a spring stretches 11 inch
1 answer:
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Answer:
I = 0.483 kgm^2
Explanation:
To know what is the moment of inertia I of the boxer's forearm you use the following formula:
(1)
τ: torque exerted by the forearm
I: moment of inertia
α: angular acceleration = 125 rad/s^2
You calculate the torque by using the information about the force (1.95*10^3 N) and the lever arm (3.1 cm = 0.031m)
Next, you replace this value of τ in the equation (1) and solve for I:
hence, the moment of inertia of the forearm is 0.483 kgm^2
Answer:
The force will be "9.8 N".
Explanation:
The given values are:
mass,
m = 0.7 kg
M = 2
g = 9.8
Now,
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then,
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On substituting the values, we get
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hence,
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On substituting the values, we get
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