Question

A block of mass 0.1 kg is attached to a spring of spring constant 22 N/m on a frictionless track. The block moves in simple harmonic motion with amplitude 0.29 m. While passing through the equilibrium point from left to right, the block is struck by a bullet, which stops inside the block. The velocity of the bullet immediately before it strikes the block is 41 m/s and the mass of the bullet is 1.23 g.
A) Find the speed of the block immediately before the collision.Answer in units of m/sB) If the simple harmonic motion after the collision is described by x = B sin(? t + f), what is the new amplitude B?Answer in units of mC) The collision occurred at the equilibrium position.How long will it take for the block to reach maximum amplitude after the collision?Answer in units of s

Answer 1

Answer:

(A) v = 14.8m/s

Explanation:

(A) V = sqrt(k/m) × A = sqrt(22/0.1) × 0.29 =14.8m/s.