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IceJOKER [234]
2 years ago
15

The system that Linnaeus developed classifies organisms by ____.

Chemistry
2 answers:
Ray Of Light [21]2 years ago
8 0
A.Genus And Species. FOR EXAMPLE HUMAN, Genus-homo And Species-sapiens Which For Homo Sapiens.
Brut [27]2 years ago
5 0

Answer is: A. Genus and species.

Carl Linnaeus (1707–1778) was a Swedish botanist, physician and zoologis.

Linnaeus discovered binomial nomenclature (system of naming organisms).

Binomial nomenclature or binary nomenclature is a formal system of naming species composed of two parts.  

The first part of the species name identifies the genus and the second part identifies the species within the genus.

For example, Cornu aspersum  is garden snail.


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Iron (III) oxide pentahydrate formula
Nina [5.8K]

Answer:

Molecular Formula Fe2O12S3·5H2O

IUPAC Name iron(3+);tri sulfate;pentahydrate

Explanation:

4 0
3 years ago
Describe a procedure to separate a mixture of sugar black pepper and pebbles
slamgirl [31]
Put the mixture in water, the pebbles will sink, the pepper will float, and the sugar will dissolve
7 0
3 years ago
Need help on this really bad!
timofeeve [1]

Answer:

Help your self

Explanation:

7 0
2 years ago
A chemist dissolves 0.096 g of CuSO4 · 5 H2O in water and dilutes the solution to the mark in a 500-mL volumetric flask. A 6-mL
scoray [572]

Answer:

(A) 4.616 * 10⁻⁶ M

(B) 0.576 mg CuSO₄·5H₂O

Explanation:

  • The molar weight of CuSO₄·5H₂O is:

63.55 + 32 + 16*4 + 5*(2+16) = 249.55 g/mol

  • The molarity of the first solution is:

(0.096 gCuSO₄·5H₂O ÷ 249.55 g/mol) / (0.5 L) = 3.847 * 10⁻⁴ M

The molarity of CuSO₄·5H₂O is the same as the molarity of just CuSO₄.

  • Now we use the dilution factor in order to calculate the molarity in the second solution:

(A) 3.847 * 10⁻⁴ M * 6mL/500mL = 4.616 * 10⁻⁶ M

To answer (B), we can calculate the moles of CuSO₄·5H₂O contained in 500 mL of a solution with a concentration of 4.616 * 10⁻⁶ M:

  • 4.616 * 10⁻⁶ M * 500 mL = 2.308 * 10⁻³ mmol CuSO₄·5H₂O
  • 2.308 * 10⁻³ mmol CuSO₄·5H₂O * 249.55 mg/mmol = 0.576 mg CuSO₄·5H₂O
5 0
3 years ago
Give the electron configuration for F.
postnew [5]

Answer:

1s² 2s² 2p⁵

Explanation:

The elements of group 17 are called halogens. These are six elements Fluorine, Chlorine, Bromine, Iodine, Astatine. Halogens are very reactive these elements can not be found free in nature. Their chemical properties are resemble greatly with each other. As we move down the group in periodic table size of halogens increases that's way fluorine is smaller in size as compared to other halogens elements. Their boiling points also increases down the group which changes their physical states. i.e fluorine is gas while iodine is solid.

Properties of fluorine:

1. it is yellow in color.

2. it is flammable gas.

3. it is highly corrosive.

4. fluorine has pungent smell.

5. its reactions with all other elements are very vigorous except neon, oxygen, krypton and helium.  

6. Its atomic number of 9.

7. its atomic mass is 18.99 amu.

Electronic configuration:

₉F = 1s² 2s² 2p⁵

4 0
3 years ago
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