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zubka84 [21]
3 years ago
13

g If a small amount of a strong acid is added to a buffer made up of a weak acid, HA, and the sodium salt of its conjugate base,

NaA, the pH of the buffer solution does not change appreciably because
Chemistry
1 answer:
ikadub [295]3 years ago
5 0

Answer:

Explanation is in the answer

Explanation:

The pH of the buffer solution does not change appreciably because the strong acid (free H⁺) reacts with conjugate base of buffer producing more weak acid. pH formula of buffers is (Henderson-Hasselbalch formula):

pH = pKa + log ( [A⁻] / [HA] )

The addition of strong acid decreases [A⁻] increasing [HA]. pH change just in the log of the ratio of [A⁻] with [HA], that is a real little effect over pH of the buffer solution.

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Answer:

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Explanation:

Hello there!

In this case, for this neutralization reaction, it is possible to realize that one the neutralization products is water (pH=7) and the other one is the salt coming up from the cation of the NaOH and the anion of the HI:

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Moreover, since the solubility of NaI is large in water, we infer it remains aqueous whereas the water is maintained as liquid:

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