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My name is Ann [436]
3 years ago
7

What is the acceleration of a softball if it hits the ground with a force 0.50 kg and hits the catchers glove with a force of 25

newtons?
Physics
1 answer:
Rom4ik [11]3 years ago
5 0

Acceleration of the ball is 50 m/s^2

Explanation:

The acceleration of the ball can be found by using Newton's second law of motion, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

F=ma

where

F is the net force

m is the mass

a is the acceleration

For the ball in this problem, we have

m = 0.50 kg (mass)

F = 25 N (force)

thereofre, the acceleration of the ball is

a=\frac{F}{m}=\frac{25}{0.50}=50 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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Name the distance that is 10 times smaller than centimeter
Svetllana [295]
1 millimeter.

1 centimeter is 1/100th of a meter (1 cent of a meter). 
1 millimeter is 1/1000th of a meter.
6 0
3 years ago
There are two blocks: one large one initially at rest, and a smaller one, initially moving to the right withsome speed. The smal
KATRIN_1 [288]

Answer:

Explanation:

Let the initial velocity of small block be v .

by applying conservation of momentum we can find velocity of common mass

25 v = 75 V , V is velocity of common mass after collision.

V = v / 3

For reaching the height we shall apply conservation of mechanical energy

1/2 m v² = mgh

1/2  x 75 x V² = 75 x g x 10

V² = 2g x 10

v² / 9 = 2 x 9.8 x 10

v² = 9 x 2 x 9.8 x 10

v = 42 m /s

small block must have velocity of 42 m /s .

Impulse by small block on large block

= change in momentum of large block

= 75 x V

= 75  x 42 / 3

= 1050 Ns.

6 0
4 years ago
I'm completely stumped as to how to do this.
worty [1.4K]

Explanation:

You have already determined the components of the known forces so I won't repeat your work here. Since the resultant force \vec{\textbf{R}} and F1 are completely along the x-axis, we can conclude that

F_{2y} = F_{3y} \Rightarrow F_{3y} = F_3\cos{\theta} = 250\:\text{lb}

We can now solve for the magnitude of F_3:

F_3 = \sqrt{F_{3x}^2 + F_{3y}^2} = \sqrt{(467)^2 + (250)^2}

\:\:\:\:=529.7\:\text{lb}

The angle \theta is then

\tan{\theta} = \dfrac{F_{3y}}{F_{3x}} = \dfrac{250}{467}

or

\theta = 49.2°

6 0
3 years ago
4) A 350 kg aircraft experiences a NET force of 1,184 N at take off.
xenn [34]

Answer:

3.4 m/s^2

Explanation:

The acceleration of the aircraft can be found by using Newton's second law:

F = ma

where

F is the net force on the aircraft

m is the mass

a is the acceleration

For the aircraft in this problem,

F = 1184 N

m = 350 kg

Solving the formula for the acceleration, we find

a=\frac{F}{m}=\frac{1184}{350}=3.4 m/s^2

6 0
3 years ago
3. When does the iron core in an electromagnet become magnetic?​
rosijanka [135]

Answer: When electricity flows through it.

Explanation:

The electromagnet exhibits magnetic properties only as soon as current flows through the nucleus. Namely, the electric current in the space around the electrical conductor through which it passes creates a magnetic field. Unlike a permanent magnet, which has a permanent property of magnetism, the electromagnet is a temporary magnet because the magnetic field also disappears when the current ceases.

3 0
4 years ago
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