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Liono4ka [1.6K]
3 years ago
10

1. A goal is scored in soccer when_____. (1 point)

Physics
2 answers:
MAXImum [283]3 years ago
7 0
1. none of the above, because the ball must go inside the net 
5. shooting
6. none of the above. the only skill that the goalie has that the rest dont have is using his hands to stop the ball from getting into the net
7. heading. if done incorrectly can seriously be dangerous
8. dribbling

VikaD [51]3 years ago
6 0

Answer:

1. The ball crosses the goal line 2 Instep 3. Trapping 4. Trapping 5. Shooting 6. Punting 7. Heading 8. Dribbling 9. Throw-in 10. Thigh Trap.

Hope this helps!

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One speaker generates sound waves with amplitude A.
raketka [301]

Answer:

iv) It is 9x bigger than before

Explanation:

As the amplitudes of the new speakers add directly with the original one, taking into account the phase that they have, the composed amplitude of the sound wave is as follows:

At = A + 4A -2A = 3 A

The intensity of the wave, assuming it propagates evenly in all directions, is constant at a given distance from the source, and can be expressed as follows:

I = P/A

where P= Power of the wave source, A= Area (for a point source, is equal to the surface area of a sphere of radius r, where is r is the distance to the source along a straight line)

For a sinusoidal wave, the power is proportional to the square of the amplitude, so the intensity is proportional to the square of the amplitude also.

If the amplitude changes increasing three times, the change in intensity will be proportional to the square of the change in amplitude, i.e., it will be 9 times bigger.

So, the statement iv) is the right one.

7 0
3 years ago
The mass of a planet is 3.7 x 1024 kg. If the planet has a radius of 9.2 x 106 m what is the acceleration of gravity for a perso
nalin [4]

Explanation:

It s given that,

Mass of a planet, M=3.7\times 10^{24}\ kg

Radius of a planet, R=9.2\times 10^{6}\ m

(1) We need to find the acceleration due to gravity for a person on the surface of the planet. Its formula is given by :

g=\dfrac{GM}{R^2}

g=\dfrac{6.67\times 10^{-11}\ Nm^2/kg^2\times 3.7\times 10^{24}\ kg}{(9.2\times 10^{6}\ m)^2}

g=2.91\ m/s^2

(2) The escape velocity is given by :

v=\sqrt{\dfrac{2GM}{R}}

v=\sqrt{{\dfrac{2\times 6.67\times 10^{-11}\ Nm^2/kg^2\times 3.7\times 10^{24}\ kg}{9.2\times 10^{6}\ m}}

v = 7324.61 m/s

Hence, this is the required solution.

3 0
3 years ago
The weather conditions
bixtya [17]

Answer:

ok confusion but we could figure it out right

Explanation:

<h3>dhdjhdndnd but its fine how was your day tho </h3>
4 0
3 years ago
I need your opinion on this
DiKsa [7]
Block that fool, move on, take a nice warm bath, but on some music and vibe dawg, it might be hard to get over something like this, but just know that person was in the wrong the whole time.
5 0
3 years ago
Blythe and Geoff are ice-skating together. Blythe has a mass of 40 kg and Geoff has a mass of 79 kg. Blythe pushes Geoff in the
Deffense [45]
9.9 m/s

calculations below 

4 0
3 years ago
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