For any object thrown upwards where only the force of gravity is acting upon it, uses the following formula for the maximum height attained.
H= v²/2g, where g = 9.81 m/s²
There are two information of velocities are given. However, we use the 20 m/s information because this is the launch velocity. Hence, the solution is as follows:
H = (20 m/s)²/2(9.81 m/s²)
<em>H = 20.4 m</em>
Answer:
The speed of the large cart after collision is 0.301 m/s.
Explanation:
Given that,
Mass of the cart,
Initial speed of the cart,
Mass of the larger cart,
Initial speed of the larger cart,
After the collision,
Final speed of the smaller cart, (as its recolis)
To find,
The speed of the large cart after collision.
Solution,
Let is the speed of the large cart after collision. It can be calculated using conservation of momentum as :
So, the speed of the large cart after collision is 0.301 m/s.
Question
What was the change in potential energy of the sheep?
Answer:
1962(m) J
Explanation:
Potential energy is given by
PE=mgh
Change in potential energy is given by
∆PE=mg(h2-h1)
Where ∆PE is the change in potential eneegy, g is acceleration due to gravity, h2 is final height and h1 is the initial height.
Substituting 9.81 m/s² for g, 1200 m for h2 and 1000 m for h1 then
∆PE=m*9.81(1200-1000)=1962m Joules
Since we are not given the mass of rhe sheep, the answer will be 1962(m) Joules
Answer:
Explanation:
We know that heat relates to mass, specific heat and variation of temperature experimented because of this heat through the equation . The heat released by the unknown material is absorbed by water, so we have , and we can write:
Since thermal equilibrium is reached we know that , where we have added to convert the temperature from Celsius to Kelvin, as <em>we must do</em>. Since we want the specific heat of the unknown material, we do:
Which for our values is: