The equation of the car is given by the equation,
x(t) = 2.31 + 4.90t² - 0.10t⁶
If we are going to differentiate the equation in terms of x, we get the value for velocity.
dx/dt = 9.8t - 0.6t⁵
Calculate for the value of t when dx/dt = 0.
dx/dt = 0 = (9.8 - 0.6t⁴)(t)
The values of t from the equation is approximately equal to 0 and 2.
If we substitute these values to the equation for displacement,
(0) , x = 2.31 + 4.90(0²) - 0.1(0⁶) = 2.31
(2) , x = 2.31 + 4.90(2²) - 0.1(2⁶) = 15.51
Thus, the positions at the instants where velocity is zero are 2.31 and 15.51 meters.
This type of system is an example of open system because the vapors leave the system and goes into the atmosphere.
<h3>
What is open system?</h3>
An open system is a type of system that has external interactions which means energy, or material transfers into or out of the system.
So we can conclude that this type of system is an example of open system because the vapors leave the system and goes into the atmosphere.
Learn more about system here: brainly.com/question/14323743
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Gravity is 9.81m/s^2 on earth F=m×g
100N=(x)kg×9.81m/s^2
x=10.19kg or more than 22lbs
