The grams of Na that are needed to complete to react with 40..0 g of O2 is calculated as below
find the moles of O2 used = mass/molar mass
= 40 g/32g/mol = 1.25 moles
write the reacting equation
4Na+ O2 = 2Na2O
by use of mole ratio between Na to O2 which is 4 :1
the moles of Na = 1.25 x 4 = 5 moles
mass of Na = mass x molar mass
= 5 moles x 23 g /mol= 115 moles
Since the leaving ability of the halide ions increasees as the basicity of the halide decreases.
If the basicity of the halide decreases as the its conjugate acid is strong.
Since the pKa value of conjuage acid of haldie is 3, it is a weak acid. So, it halide is not a good leaving group.
Therefore the answer is No, because a good leaving group is the conjugate base of a strong acid. The halide not acidic enough to be a good leaving group.
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