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weeeeeb [17]
3 years ago
9

A student has one mole of zinc and one mole of oxygen. Which of the following is true for both samples? *

Chemistry
1 answer:
Otrada [13]3 years ago
6 0

Answer:

2

Explanation:

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What is the formula of Potassium hydroxide? What is it common name? Is it Alkali?​
seropon [69]
___________________________

Question: What is the formula of Potassium hydroxide? What is it common name? Is it Alkali?

Answer: The formula of Potassium hydroxide is KOH. It's common name is Caustic Potash. Yes, it is alkali because Potassium is the most reactive metal.
It is very strong base because it has potassium atom which is the most reactive element. It turns red litmus paper into blue which proves that it is basic in nature.

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8 0
4 years ago
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Oh, no! You just spilled 85.00 mL of 1.500 M sulfuric acid on your lab bench and need to clean it up immediately! Right next to
vredina [299]

Explanation:

We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.

   H_2SO_4(aq) + 2NaHCO_3(s) \rightarrow Na2SO_4(aq) + 2H_2O(l) + 2CO_2(g)

Next we will calculate how many moles of H_2SO_4 are present in 85.00 mL of 1.500 M sulfuric acid.

As,       Molarity = \frac{\text{moles of solute}}{\text{liters of solution
}}

            1.500 M = \frac{n}{0.08500 L
}

                    n = 0.1275 mol H_2SO_4

Now set up and solve a stoichiometric conversion from moles of H_2SO_4  to grams of NaHCO_3. As, the molar mass of NaHCO_3 is 84.01 g/mol.

 0.1275 mol H_2SO_4 \times (\frac{2 mol NaHCO_3}{1 mol H_2SO_4}) \times (\frac{84.01 g NaHCO_3}{1 mol NaHCO_3})

                 = 21.42 g NaHCO_3

So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.

4 0
3 years ago
If a person weighs 87lbs and has to be given a drug with a dosage of 50 milligrams per kilogram body weight, how many grams of t
Katarina [22]

Answer:

1 957,5

Explanation:

87libs=39.5kg that equals 50=1.957.5

7 0
3 years ago
What is the empirical formula of ascorbic acid, given that the pseudoformula is C3.407 H4.53 O3.406??
Tom [10]
To determine the empirical formula of ascorbic acid, we divide the lowest fraction with the other values. For this case, we divide everything with 3.406. We do as follows:

C = 3.407 / 3.406 = 1
H = 4.53 / 3.406 = 1.33
O = 3.406 / 3.406 = 1

So, you have CHO

Hope this answers the question. Have a nice day.
4 0
4 years ago
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FREE BRAINIEST WHO WANTS IT?!!!
tia_tia [17]

Ngl, I really want it! But how do I know you're not scamming?

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3 years ago
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