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Elena-2011 [213]
3 years ago
5

Ask a 1 grade question and my brother will answer it

Mathematics
2 answers:
Sliva [168]3 years ago
7 0
10 +10 good luck have fun
sashaice [31]3 years ago
4 0

what is 5 times 3

hope this helps

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Use the drop-downs to identify the domain and range of the following relation.
Orlov [11]

Answer:Domain is x and range is y.For ex:-4 is domain and -7 is range.

Step-by-step explanatioFeel pleasure to help u:

5 0
3 years ago
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Can i get help on this one ? im almost running our of points i would give 50 but i need more ;-; anyway
JulsSmile [24]

Answer:

Step-by-step explanation:

Let x = third side

Using the Triangle Inequality theorem which states that the sum of two sides of a triangle must be longer than the third side and the difference of the two sides is the lower limit of the third side, the answer to your question is that the third side must be between 3 and 13, or written using inequalities, 3 < third side (or x) < 13 is the range.

4 0
3 years ago
A recipe calls for 4 cups of flour. Lauren wants to make 20% more servings than the recipe makes. Which expression represents ho
ale4655 [162]
C. 6/5 * 4

6/5 = 1.20 where .20 represents the 20% increase in serving.

1.20 * 4 = 4.8 is the total cups of flour needed to increase serving by 20%

4 is the 100% ; the desired increase is 20%; therefore: 100% + 20% = 120% based on 4 cups. So, 120% ÷ 100% = 1.2 * 4 = 4.80 cups
6 0
3 years ago
Cos (90-theta) • cosec90-theta) =tano. How?​
denis-greek [22]

Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

  • \cos (90 - \alpha  ) = \sin \alpha  or  \sin(90 - \alpha ) = \cos\alpha
  • cosec \: (90 - \alpha  ) = \sec\alpha   or  \sec(90 - \alpha ) = cosec\:\alpha

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

  • <u></u>\sin \alpha = \frac{1}{cosec \: \alpha }  or  cosec \: \alpha  = \frac{1}{\sin \alpha }
  • <u></u>\cos \alpha = \frac{1}{\sec \alpha }  or  \sec \alpha = \frac{1}{\cos \alpha }

<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

\cos (90 - \alpha ) \times cosec(90 - \alpha )

=> sin\alpha  \times \sec\alpha

=> \sin\alpha  \times \frac{1}{\cos\alpha }

=> \frac{\sin\alpha }{\cos\alpha }

=> \tan\alpha = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0
3 years ago
If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen
adell [148]

Answer:

option D

2x − 7(−3x − 17) = 4

Step-by-step explanation:

Given in the question two equations

<h3>Equation 1</h3>

2x - 7y = 4

<h3>Equation 2</h3>

3x + y = -17

Rearranging equation 2 in terms of y

3x + y = -17

y = -17 - 3x

Put this value of y in Equation 1

2x - 7y = 4

2x - 7(-17 - 3x) = 4

So,

If you use the substitution method to solve the following system, new equation will be

<h3>2x - 7(- 3x - 17) = 4 </h3>

3 0
3 years ago
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