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Dimas [21]
3 years ago
11

Stu wanted to calculate the resistance of a light bulb

Physics
2 answers:
d1i1m1o1n [39]3 years ago
5 0

Answer:

Stu's answer was incorrect. According to Ohm's law, R = V/I. This is the equation that should be used to obtain the correct answer, which is 8 ohms.

Explanation:

Nonamiya [84]3 years ago
3 0

Answer:

yes

Explanation:

He used the formula R = VI and obtained an

answer of 2

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What is capacitance?
Otrada [13]

Answer:

A, the amount of charge stored per volt

Explanation:

The equation for capacitance is

C = Q/V

therefore, it is charge per volt

5 0
4 years ago
What equation is used to calculate momentum
Dmitrij [34]

Answer:

p = m v

Explanation:

You can see from the equation that momentum is directly proportional to the object's mass (m) and velocity (v). Therefore, the greater an object's mass or the greater its velocity, the greater its momentum. A large, fast-moving object has greater momentum than a smaller, slower object.

6 0
3 years ago
Look at the pendulum diagram. at which point is the kinetic energy of the pendulum the greatest
damaskus [11]

Position <em>' C '</em> is the middle of the swing.  That's where the weight is the lowest.

It's also the place where the weight is moving the fastest, so that means it's the place where the kinetic energy is greatest.

8 0
4 years ago
Read 2 more answers
We can model the human back as a pivoted rod?
3241004551 [841]

Answer:

So the answer is yes, we can the back be shaped like a spinning rod

spinal column that is approximated by a long and narrow rod,

Explanation:

The bone system of the body is very well modeled in physics, the back has a spinal column that is approximated by a long and narrow rod, this rod is fixed in the lower part to the coccyx and has a weight in the upper part (head), this rod has longitudinal vertical movement and twisting movement around the lower part of the bar.

So the answer is yes, we can the back be shaped like a spinning rod

7 0
3 years ago
An object is taken from an oven at 350o F and left to cool in a room at 70o F. If the temperature fell to 250o F in one hour, wh
Oksana_A [137]

Answer:

117.83° F

Explanation:

Using Newton's Law of Cooling which can be expressed as:

\dfrac{dT}{dt}= k(T-T_1)

The differential equation can be computed as:

\dfrac{dT}{dt}= k(T-70)

\dfrac{dT}{(T-70)}= kdt

\int \dfrac{dT}{(T-70)}= \int kdt

In|T-70| = kt +C

T- 70 = e^{kt+C} \\ \\ T = 70+e^{kt+C} \\ \\ T = 70 + C_1e^{kt}  --- (1)

where;

C_1 = e^C

At the initial condition, T(0)= 350

350 = 70 C_1^{k*0}

350 -70 = C_1

280 = C_1

replacing C_1= 280 into (1)

Hence, the differential equation becomes:

T(t) = 70 + 280 e^{kt}

when;

time (t) = 1 hour

T(1) = 250

Since;

250 = 70 + 280 e^{k*1}

180 = 280e^k \\ \\ \dfrac{180}{280}= e^k

k = In (\dfrac{180}{280})

k = -0.4418

Therefore;

T(t) = 70 + 280e^{(-0.4418)}t

After 4 hours, the temperature is:

T(t) = 70 + 280e^{(-0.4418)}4

T(4) = 117.83° F

7 0
3 years ago
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