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Tems11 [23]
3 years ago
5

Set up differential equation of angular S.H.M​

Physics
1 answer:
3241004551 [841]3 years ago
3 0

Answer:

{ \sf{ \omega \: is \: the \: angular \: velocity}} \\ { \sf{ \theta \: is \: the \: angular \: displacement}}

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a projectile is shot horizontally from the edge of a cliff, 230m above the ground. the projectile lands 300m from base of the cl
bekas [8.4K]

Answer:

The time taken by the projectile to hit the ground is 6.85 sec.

Explanation:

Given that,

Vertical height of cliff = 230 m

Distance = 300 m

Suppose, determine the time taken by the projectile to hit the ground.

We need to calculate the time

Using second equation of motion

s=ut+\dfrac{1}{2}gt^2

Where, s = vertical height of cliff

u = initial vertical velocity

g = acceleration due to gravity

Put the value in the equation

230=0+\dfrac{1}{2}\times9.8\times t^2

t=\sqrt{\dfrac{230\times2}{9.8}}

t=6.85 sec

Hence, The time taken by the projectile to hit the ground is 6.85 sec.

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3 years ago
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Answer:

0.25

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2.5

Explanation:

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3 years ago
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How many grams are in 238 moles of arsenic
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A race car accelerates uniformly at 14.2 m/s2. If the race car starts from rest how fast will it
Kaylis [27]

Answer:

vf=94.4 m/s

Explanation:

acceleration is the final velocity minus initial velocity divided by time

a = (vf-vi)/t

Given:

a= 14.2 m/s^2

vi= 0 (at rest)

t = 6.6

Solve for vf

a = (vf-vi)/t

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3 years ago
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