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Tems11 [23]
3 years ago
5

Set up differential equation of angular S.H.M​

Physics
1 answer:
3241004551 [841]3 years ago
3 0

Answer:

{ \sf{ \omega \: is \: the \: angular \: velocity}} \\ { \sf{ \theta \: is \: the \: angular \: displacement}}

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I've been on this for a while please help me
True [87]

Answer: Student 2

Explanation: Iron nail and a paperclip are conductors because they are made of metal. A rock, rubber band, and wooden stick are insulators because they cannot conduct electricity.

7 0
3 years ago
A wire has a diameter of 2. 0 mm and a length of 32 m, and is found to have a resistance of 1. 8 ω. what is the resistivity of t
Anna35 [415]

A wire has a diameter of 2. 0 mm and a length of 32 m and is found to have a resistance of 1. 8 ω having a resistivity of the wire

Resistivity, which is frequently denoted by the letter rho, is mathematically equal to the resistance R of a specimen, such as a wire, multiplied by its cross-sectional area A, and divided by its length l; it is represented by the symbol RA/l. The ohm is the unit of resistance.

A conductor's resistance (R) is inversely proportional to its length (L), with R L. We now know the variables that affect resistivity. Ohm's law and resistors have also been covered in relation to parallel formulae.

The resistance provided by the substance per unit length for unit cross-section is referred to as a conductor's resistivity. Temperature and pressure affect the material's resistivity, which is a property. When compared to the resistivity of insulators, conductors have a low resistivity.

To learn more about resistivity please visit  -
brainly.com/question/13612460
#SPJ4

8 0
1 year ago
A sealed tank containing seawater to a height of 10.5 mm also contains air above the water at a gauge pressure of 2.95 atmatm. W
weqwewe [10]

Answer:

The water is flowing at the rate of 28.04 m/s.

Explanation:

Given;

Height of sea water, z₁ = 10.5 m

gauge pressure, P_{gauge \ pressure} = 2.95 atm

Atmospheric pressure, P_{atm} = 101325 Pa

To determine the speed of the water, apply Bernoulli's equation;

P_1 + \rho gz_1 + \frac{1}{2}\rho v_1^2 = P_2 + \rho gz_2 + \frac{1}{2}\rho v_2^2

where;

P₁ = P_{gauge \ pressure} + P_{atm \ pressure}

P₂ = P_{atm}

v₁ = 0

z₂ = 0

Substitute in these values and the Bernoulli's equation will reduce to;

P_1 + \rho gz_1 + \frac{1}{2}\rho v_1^2 =  P_2 + \rho gz_2 + \frac{1}{2}\rho v_2^2\\\\P_1 + \rho gz_1 + \frac{1}{2}\rho (0)^2 =  P_2 + \rho g(0) + \frac{1}{2}\rho v_2^2\\\\P_1 + \rho gz_1 =  P_2 + \frac{1}{2}\rho v_2^2\\\\P_{gauge} + P_{atm} + \rho gz_1 = P_{atm} + \frac{1}{2}\rho v_2^2\\\\P_{gauge} +  \rho gz_1 =  \frac{1}{2}\rho v_2^2\\\\v_2^2 = \frac{2(P_{gauge} +  \rho gz_1)}{\rho} \\\\v_2 = \sqrt{ \frac{2(P_{gauge} +  \rho gz_1)}{\rho} }

where;

\rho is the density of seawater = 1030 kg/m³

v_2 = \sqrt{ \frac{2(2.95*101325 \ + \  1030*9.8*10.5 )}{1030} }\\\\v_2 = 28.04 \ m/s

Therefore, the water is flowing at the rate of 28.04 m/s.

7 0
3 years ago
What is the value of work done on an object when a
tino4ka555 [31]
W = F * s
Here, F = 50 N
s = 15 m

Substitute their values, 
W = 50 * 15
W = 750 J

In short, Your Answer would be 750 Joules

Hope this helps!
7 0
3 years ago
Which forces always push in the opposite direction of motion slow stuff down.
VARVARA [1.3K]
Friction- the external force that acts on objects and causes them to slow down when no other external force acts upon them.
8 0
3 years ago
Read 2 more answers
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