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Lisa [10]
3 years ago
12

The displacement vector from your house to the library is 740 m long, pointing 40 ∘ north of east. Part A What are the x-compone

nt (x-axis is directed from west to east) of this displacement vector?
Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0

The horizontal component of the displacement is 566.9 m

Explanation:

The horizontal (x-) and vertical (y-) components of a vector on the Cartesian plane can be found as follows:

v_x = v cos \theta

v_y = v sin \theta

where

v is the magnitude of the vector

\theta is the angle representing the direction of the vector, measured as above the x-axis.

In this problem, we have:

v = 740 m (magnitude of the vector)

\theta=40^{\circ} (direction of the vector)

Therefore, the two components are

v_x = (740)(cos 40)=566.9 m

v_y = (740)(sin 40)=475.7 m

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

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Hans Full is pulling on a rope to drag his backpack to school across the ice. He pulls upwards and rightwards with a force of 22
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Explanation:

From the question given above, the following data were obtained:

Force (F) = 22.9 N

Angle (θ) = 35°

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Workdone (Wd) =?

The work done can be obtained by using the following formula:

Wd = Fd × Cos θ

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Chanice drives her scooter 7 kilometers north. she stops for lunch and then drives 5 kilometers and then 1 km east again. what d
lord [1]

Distance covered is given as follows

1). 7 km North

2). 5 km North

3). 1 km East

Now total distance covered will be given as

d = d_1 + d_2 + d_3

d = 7 km + 5 km + 1 km

d = 13 km

Now in order to find the displacement we will show all with their directions

\vec d_1 = 7 + 5 = 12 km towards North

\vec d_2 = 1 km towards East

So total displacement is

\vec d = \vec d_1 + \vec d_2

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so net displacement will be

d = \sqrt{12^2 + 1^2} = 12.04 km

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