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Lisa [10]
3 years ago
12

The displacement vector from your house to the library is 740 m long, pointing 40 ∘ north of east. Part A What are the x-compone

nt (x-axis is directed from west to east) of this displacement vector?
Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0

The horizontal component of the displacement is 566.9 m

Explanation:

The horizontal (x-) and vertical (y-) components of a vector on the Cartesian plane can be found as follows:

v_x = v cos \theta

v_y = v sin \theta

where

v is the magnitude of the vector

\theta is the angle representing the direction of the vector, measured as above the x-axis.

In this problem, we have:

v = 740 m (magnitude of the vector)

\theta=40^{\circ} (direction of the vector)

Therefore, the two components are

v_x = (740)(cos 40)=566.9 m

v_y = (740)(sin 40)=475.7 m

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

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How much WATER needed to offset the force of jumping down from 20metre in vacuum environment,to keep me alive.
kenny6666 [7]

Answer:

it's quite difficult

Explanation:

6 0
2 years ago
A ceiling fan with 90-cm-diameter blades is turning at 64 rpm . Suppose the fan coasts to a stop 28 s after being turned off. Wh
mixas84 [53]

Answer:

the speed of the tip of a blade 10 s after the fan is turned off is 16.889 m/s.

Explanation:

Given;

diameter of the ceiling fan, d = 90 cm = 0.9 m

angular speed of the fan, ω = 64 rpm

time taken for the fan to stop, t = 28 s

The distance traveled by the ceiling fan when it comes to a stop is calculated as;

d = vt = \omega r\times  t= ( \frac{64 \ rev}{\min} \times \frac{2 \pi \ rad}{rev} \times \frac{1 \min}{60 \ s} \times 0.9 \ m) \times 28 \ s\\\\d = 168.89 \ m

The speed of the tip of a blade 10 s after the fan is turned off is calculated as;

v = \frac{d}{t} \\\\v = \frac{168.89}{10} \\\\v = 16.889 \ m/s

Therefore, the speed of the tip of a blade 10 s after the fan is turned off is 16.889 m/s.

4 0
3 years ago
Which best describes the electric field created by a positive charge?
Vlad [161]
Its rays point away from the charge
3 0
3 years ago
Read 2 more answers
A positively charged particle 1 is at the origin of a Cartesian coordinate system, and there are no other charged objects nearby
8090 [49]

Answer:

P=(2 nm, 8mn)

Explanation:

Given :

Position of positively charged particle at origin, O=(0\ nm,0\ nm)

Position of desired magnetic field, D\equiv(1\ nm,8\ nm)

Magnitude of desired magnetic field, E=0\ N.C^{-1}

Let q be the positive charge magnitude placed at origin.

<u>We know the distance between the two Cartesian points is given as:</u>

d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

<u>For the electric field effect to be zero at point D we need equal and opposite field at the point.</u>

\frac{1}{4\pi.\epsilon_0} \times \frac{q}{r^2 } =\frac{1}{4\pi.\epsilon_0} \times \frac{q}{r^2 }

\therefore (1-0)^2+(8-0)^2=r^2

r^2=65\ nm

r=\sqrt{65}

as we know that the electric field lines emerge radially outward of a positive charge so the second charge will be at equally opposite side of the  given point.

assuming that the second charge is placed at (x,y) nano-meters.

Therefore,

x=2\times 1=2\ nm

and

y=2\times 8=16\ nm

3 0
3 years ago
The solar system is made up of eight planets, numerous comets, asteroids and moons, and the Sun. The force that holds all of the
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Your answer is Gravity


Hope this could help :)

5 0
2 years ago
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