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Lisa [10]
3 years ago
12

The displacement vector from your house to the library is 740 m long, pointing 40 ∘ north of east. Part A What are the x-compone

nt (x-axis is directed from west to east) of this displacement vector?
Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0

The horizontal component of the displacement is 566.9 m

Explanation:

The horizontal (x-) and vertical (y-) components of a vector on the Cartesian plane can be found as follows:

v_x = v cos \theta

v_y = v sin \theta

where

v is the magnitude of the vector

\theta is the angle representing the direction of the vector, measured as above the x-axis.

In this problem, we have:

v = 740 m (magnitude of the vector)

\theta=40^{\circ} (direction of the vector)

Therefore, the two components are

v_x = (740)(cos 40)=566.9 m

v_y = (740)(sin 40)=475.7 m

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

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Ber [7]
<h3>answer</h3>

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At top-most point velocity is v

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4 0
3 years ago
PLEASE HELP ME :)
ddd [48]

A) 350 J

- The initial internal energy of the cup is

U_i = 230 J

- The final internal energy of the cup is

U_f = 580 J

According to the first law of thermodynamics:

U_f - U_i = Q+W

where

Q is the heat absorbed by the system

W is the work done on the system

The work done on the system in this case is 0, so we can rewrite the equation as

U_f - U_i = Q

And so we find the heat transferred

Q=580 J - 230 J=350 J

B) IN the cup

Explanation:

in this situation, we see that the internal energy of the cup increases. The internal energy of an object/substance is proportional to its temperature, so it is a measure of the average kinetic energy of the molecules of the object/substance. Therefore, in this case, the temperature (and the energy of the molecules of the substance) has increased: this means that heat has been transferred INTO the system from the environment (the heat came from the sun).

8 0
3 years ago
A student pulls horizontally on a block with a spring scale. The block reads 24.5 Newtons before the block starts to move. It re
Ahat [919]

Answer:

The coefficient of friction causes the force on the object to be less than its initial reading on the spring scale.

Explanation:

Since the block reads 24.5 N before the block starts to move, this is its weight. Now, when the block starts to move at a constant velocity, it experiences a frictional force which is equal to the force with which the student pulls.

Now, since the velocity is constant so, there is no acceleration and thus, the net force is zero.

Let F = force applied and f = frictional force = μN = μW where μ = coefficient of friction and N = normal force. The normal force also equals the weight of the object W.

Now, since F - f = ma and a = 0 where a = acceleration and m = mass of block,

F - f = m(0) = 0

F - f = 0

F = f

Since the force applied equals the frictional force, we have that

F =  μW and F = 23.7 N and W = 24.5 N

So, 23.7 N = μ(24.5 N)

μ = 23.7 N/24.5 N

μ = 0.97

Since μ = 0.97 < 1, the coefficient of friction causes the force on the object to be less than its initial reading on the spring scale.

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Answer:

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