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mart [117]
3 years ago
12

In this diagram, bac~edf. if the area of bac= 6 in.², what is the area of edf? PLZ HELP PLZ PLZ PLZ

Mathematics
1 answer:
NemiM [27]3 years ago
5 0

Answer:

2.7 in²

Step-by-step explanation:

Area of ∆BAC : ∆Area of EDF = BC² : EF² (based on the area of similar triangles theorem)

Thus:

6 in^2 : x in^2 = (3 in)^2 : (2 in)^2

\frac{6}{x} = \frac{3^2}{2^2}

\frac{6}{x} = 2.25

\frac{6}{x}*x = 2.25*x

6 = 2.25x

\frac{6}{2.25} = \frac{2.25x}{2.25}

2.67 = x

Area of ∆EDF = 2.7 in²

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