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3 years ago

1. A rocket hits the ground at an angle of 60° from the horizontal at a speed of 300 m/s.

Physics

1 answer:

alekssr [168]3 years ago

5 0

Answer:

(a). The horizontal and vertical components are $v\cos\theta$ and $v\sin\theta$

(b). The horizontal and vertical components of the rocket's impact velocity is 150 m/s and 259.8 m/s.

Explanation:

Given that,

Angle = 60°

Speed = 300 m/s

(a). We need to draw the vector representing the rocket's impact and its components

Using given data

The components of rocket's impact

The horizontal component is

$u_{x}=u\cos\theta$

The vertical component is

$v_{v}=v\sin\theta$

(b). We need to calculate the horizontal and vertical components of the rocket's impact velocity

Using horizontal and vertical components

The horizontal component is

$v_{x}=v\cos\theta$

Put the value into the formula

$v_{x}=300\cos60$

$v_{x}=150\ m/s$

The vertical component is

$v_{x}=v\sin\theta$

Put the value into the formula

$v_{x}=300\sin60$

$v_{x}=259.8\ m/s$

Hence, (a). The horizontal and vertical components are $v\cos\theta$ and $v\sin\theta$

(b). The horizontal and vertical components of the rocket's impact velocity is 150 m/s and 259.8 m/s.

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