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anastassius [24]
3 years ago
11

1. A rocket hits the ground at an angle of 60° from the horizontal at a speed of 300 m/s.

Physics
1 answer:
alekssr [168]3 years ago
5 0

Answer:

(a). The horizontal and vertical components are v\cos\theta and v\sin\theta

(b). The horizontal and vertical components of the rocket's impact velocity is 150 m/s and 259.8 m/s.

Explanation:

Given that,

Angle = 60°

Speed = 300 m/s

(a). We need to draw the vector representing the rocket's impact and its components

Using given data

The components of rocket's impact

The horizontal component is

u_{x}=u\cos\theta

The vertical component is

v_{v}=v\sin\theta

(b). We need to calculate the horizontal and vertical components of the rocket's impact velocity

Using horizontal and vertical components

The horizontal component is

v_{x}=v\cos\theta

Put the value into the formula

v_{x}=300\cos60

v_{x}=150\ m/s

The vertical component is

v_{x}=v\sin\theta

Put the value into the formula

v_{x}=300\sin60

v_{x}=259.8\ m/s

Hence, (a). The horizontal and vertical components are v\cos\theta and v\sin\theta

(b). The horizontal and vertical components of the rocket's impact velocity is 150 m/s and 259.8 m/s.

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A physics student throws a softball straight up into the air. The ball was in the air for a total of 3.56 s before it was caught
meriva

Answer:

The initial velocity of the softball is 14.711 meters per second.

Explanation:

This is a case of an object which experiments a free fall, that is, an uniform accelerated motion due to gravity and in which effects from air friction and Earth's rotation can be neglected.

From statement we must understand that the student threw the softball upwards and it is caught at original position 3.56 seconds later. Initial and final heights, time and gravitational acceleration are known and initial speed is unknown. The following equation of motion is used:

y = y_{o} + v_{o}\cdot t + \frac{1}{2}\cdot g \cdot t^{2} (Eq. 1)

Where:

y_{o} - Initial height of the softball, measured in meters.

y - Final height of the softball, measured in meters.

v_{o} - Initial velocity of the softball, measured in meters per second.

t - Time, measured in seconds.

g - Gravitational acceleration, measured in meters per square second.

If we know that y = y_{o}, t = 3.56\,s and g = -9.807\,\frac{m}{s^{2}}, the initial velocity of the softball is:

v_{o}\cdot (3\,s)+\frac{1}{2}\cdot (-9.807\,\frac{m}{s^{2}} )\cdot (3\,s)^{2} = 0

3\cdot v_{o} -44.132\,m= 0

v_{o} = 14.711\,\frac{m}{s}

The initial velocity of the softball is 14.711 meters per second.

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You use a lever to lift a heavy tree branch you apply a force of 50 n and the lever lifts the branch
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1.8 is the mechanical advantage of the lever.

<h3>Definition of mechanical advantage</h3>

The theoretical mechanical advantage of a system is the ratio of the force that performs the useful work to the force applied, assuming there is no friction in the system.

The advantage gained by the use of a mechanism in transmitting force specifically the ratio of the force that performs the useful work of a machine to the force that is applied to the machine.

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brainly.com/question/16617083

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