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2 years ago

The gravitational pull of the sun is greatest in our solar system because it...

Physics

1 answer:

Fudgin [204]2 years ago

5 0

Answer:

B. has the greatest mass

Explanation:

mass & distance affect pull

grativy affects speed & shape of orbit of the planet

quiziz

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A body weighs less inside water

Ipatiy [6.2K]

Answer:

Body weighs lesser in water because of the upward force (buoyant force) which acts on our body thereby reducing our actual weight. This is our apparent weight.

Explanation:

hope it helps

7 0

2 years ago

What does it mean when the orbital eccentricity of a planet is close to 1?

ankoles [38]

We have that Zero signifies a perfect circle shape and 1 shows it maximum out of order shape.

From the question we are told

What does it mean when the orbital eccentricity of a planet is close to 1

Generally

Eccentricity

This in its simplest definition means to be eccentric which means to be a bit out of order or for the given subject at hand means to be a bit out of shape

Naturally the Eccentricity that an object possess is defined by two number 0(zero) to 1(one)

Where

Zero signifies a perfect circle shape and 1 shows it maximum out of order shape

For more information on this visit

brainly.com/question/17208989?referrer=searchResults

7 0

3 years ago

Read 2 more answers

I don't understand this question at all, can I please get some help?

beks73 [17]

V^2/R=180W
v=root 180R

4 0

3 years ago

The nonreflective coating on a camera lens with an index of refraction of 1.21 is designed to minimize the reflection of 570-nm

lord [1]

Answer: 117.8 nm

Explanation:

Given,

Nonreflective coating refractive index : n = 1.21

Index of refraction: $n_0$ = 1.52

Wave length of light = λ = 570 nm = $570\times10^{-9}\ m$

$\text{ Thickness}=\dfrac{\lambda}{4n}$

$=\dfrac{570\times10^{-9}\ m}{4\times1.21}\\\\\approx\dfrac{117.8\times 10^{-9}\ m}{1}\\\\=117.8\text{ nm}$

Hence, the minimum thickness of the coating that will accomplish= 117.8 nm

5 0

3 years ago

I stretch a rubber band and "plunk" it to make it vibrate in its fundamental frequency. I then stretch it to twice its length an

Nikitich [7]

Answer:

The new frequency (F₂ ) will be related to the old frequency by a factor of one (1)

Explanation:

Fundamental frequency = wave velocity/2L

where;

L is the length of the stretched rubber

Wave velocity = $\sqrt{\frac{T}{\frac{M}{L}}}$

Frequency (F₁) = $\frac{\sqrt{\frac{T}{\frac{M}{L}}}}{2*L}$

To obtain the new frequency with respect to the old frequency, we consider the conditions stated in the question.

Given:

L₂ =2L₁ = 2L

T₂ = 2T₁ = 2T

(M/L)₂ = 0.5(M/L)₁ = 0.5(M/L)

F₂ = $\frac{\sqrt{\frac{2T}{0.5(\frac{M}{L})}}}{4*L} = \frac{\sqrt{4(\frac{T}{\frac{M}{L}}})}{4*L} = \frac{2}{2} [\frac{\sqrt{\frac{T}{\frac{M}{L}}}}{2*L}] = F_1$

Therefore, the new frequency (F₂ ) will be related to the old frequency by a factor of one (1).

7 0

3 years ago