Ynhas an approximateN(np,np(1−p)). Sop(1−p) is animportant function ofpas it is in the variance ofYn. Thus, ifpis unknown, we mi
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Answer:
Step-by-step explanation:
1) if the point A has coordinates (-1;10) and the point B - (5;2), then it is possible to write common view of the required equation of the line:
2) if to substitute the coordinates of A&B into the common equation, then:
3) finally, in slope-intersection form:
3y= -4x+26; ⇔ y= -4/3 x +26/3.
P.S. the suggested way of the solution is not the only one.
Answer:
The points are: (16.12,0),(-8.12,0).
Step-by-step explanation:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots such that
, given by the following formulas:
Distance between two points:
Suppose we have two points, and
. The distance between them is given by:
Find all points on the x-axis that are 14 units from the point (4, -7).
Being on the x-axis mean that they have y-coordinate equal to 0, so the point is (x,0).
The distance is 14. So
So
The points are: (16.12,0),(-8.12,0).
We know that for each triangle made up by dashed line segment forms 30° angles, so, for example, ∠GOH is 30° and then ∠HOI is 30°
Rotating the shape 240° around the centre is the same as counting in 30°
The triangle GOH will first fit the triangle HOI then triangle IOJ and so on until it has completed 8 times 30° turn. Its final position is shown in the diagram below
Rotating the shape 240° around the centre is the same as counting in 30°
The triangle GOH will first fit the triangle HOI then triangle IOJ and so on until it has completed 8 times 30° turn. Its final position is shown in the diagram below