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pochemuha
3 years ago
9

valancy of x is 3 while that of y is 1. write a formula of the compounds when each of the seperaty combines with oxygen

Chemistry
1 answer:
Vaselesa [24]3 years ago
6 0

Answer:

X₂O₃ , Y₂O

Explanation:

Valency of an element tells how well that element can form compounds with other atoms.

It sometimes, is also determined by the number of hydrogen atoms that it combines with.

Oxygen usually has a valency of 2, or oxidation state of -2.

That means oxygen will need 2 more electrons in it's outer shell to form a configuration of a noble gas(octet configuration).

The oxidation state of an atom in a molecule gives the number of valence electrons it has gained or lost.

Assuming both X and Y are less electronegative than oxygen, X  has a valency of 3 and OS of +3.

While forming a neutral compound, we need no net charge on the compound. In X₂O₃,

total charge on X is 2 x (OS of X)= 2 x ( +3) = +6

total charge on O is 3 x (OS of O)= 3 x ( -2) = -6

Net charge is 0.

Similarly, in Y₂O

total charge on Y is 2 x (OS of Y)= 2 x ( +1) = +2

total charge on O is 1 x (OS of O)= 1 x ( -2) = -2

Net charge is 0.

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Explanation:

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3 years ago
How many significant figures are in 0.0233?
viva [34]

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7 0
3 years ago
Start with 100.00 mL of 0.10 M acetic acid, CH3COOH. The solution has a pH of 2.87 at 25 oC. a) Calculate the Ka of acetic acid
jasenka [17]

Answer: a) The K_a of acetic acid at 25^0C is 1.82\times 10^{-5}

b) The percent dissociation for the solution is 4.27\times 10^{-3}

Explanation:

CH_3COOH\rightarrow CH_3COO^-H^+

 cM              0             0

c-c\alpha        c\alpha          c\alpha

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.10 M and \alpha = ?

Also pH=-log[H^+]

2.87=-log[H^+]  

[H^+]=1.35\times 10^{-3}M

[CH_3COO^-]=1.35\times 10^{-3}M

[CH_3COOH]=(0.10M-1.35\times 10^{-3}=0.09806M

Putting in the values we get:

K_a=\frac{(1.35\times 10^{-3})^2}{(0.09806)}

K_a=1.82\times 10^{-5}

b)  \alpha=\sqrt\frac{K_a}{c}

\alpha=\sqrt\frac{1.82\times 10^{-5}}{0.10}

\alpha=4.27\times 10^{-5}

\% \alpha=4.27\times 10^{-5}\times 100=4.27\times 10^{-3}

5 0
3 years ago
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