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Serga [27]
3 years ago
5

Determine the approximate ordered pair for f(x)=g(x)

Mathematics
1 answer:
kozerog [31]3 years ago
6 0

Answer:

the graph of two linear functions negative 4 times x plus 15 times y equals negative 300 and 20 times x plus 4 times y equals negative 20

(−3, 9)

(−3, 8)

(3, −19)

(3, −8)

Step-by-step explanation:

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ASAP PLS I NEED IT AND TY
mars1129 [50]
<h2>Dilations and Scale Factors</h2>

When we're solving with scale factors, we either divide or multiply.

If the shape becomes larger, we multiply to get the new length.

If the shape becomes smaller, we divide to get the new length.

<h2>Solving the Question</h2>

We're given:

  • Original side length is 2.5 units
  • Scale factor = 6

Because the shape becomes larger, we have to multiply the original side length by the scale factor, 6, to get the new side length.

2.5 x 6 = 15

Therefore, the missing side length is 15 units.

<h2>Answer</h2>

15 units

8 0
1 year ago
Read 2 more answers
A professional baseball diamond is a square. The distance from base to base is 90 ft. To the nearest foot, how far does a catche
mamaluj [8]

BSE is square.

Let side be s

  • s=90ft

Diagonal be d

\\ \tt\longmapsto s=\dfrac{d}{\sqrt{2}}

\\ \tt\longmapsto d=s\sqrt{2}

\\ \tt\longmapsto d=90\sqrt{2}

\\ \tt\longmapsto d=127ft

3 0
2 years ago
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The density of mercury is 13.6 grams per cubic centimeter. Complete the steps for converting 13.6 g/cm^3 to kg/m^3
Mama L [17]

1 cubic meter = 100 cm * 100 cm * 100 cm = 1 x 10^6 cc

1 kilogram = 1,000 grams

13.6 g / cc

If we had a cubic meter of mercury, its mass would be (or it would "weigh") 13.6 * 1,000,000 = 13,600,000 grams or 13,600 kilograms.

And so its density would be 13,600 kg / cubic meter.


4 0
3 years ago
Find the missing value can someone help me get this
Mashutka [201]

Answer:

-3

Step-by-step explanation:

-5 = -8 - (- 3)

5 0
3 years ago
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3) Rita has 3/4 m of Ifugao cloth. She used 2/3 m for placement. What part
enot [183]

Answer:

Unused = \frac{1}{12}m

Step-by-step explanation:

Given

Total= \frac{3}{4}m

Used= \frac{2}{3}m

Required

Determine the part left

The part left is calculated using:

Used + Unused = Total

Unused = Total - Used

Unused = \frac{3}{4}m - \frac{2}{3}m

Take LCM

Unused = \frac{9m - 8m}{12}

Unused = \frac{1m}{12}

Unused = \frac{1}{12}m

6 0
2 years ago
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