Answer:
velocity of the plane = 274 miles/hour at 30.9⁰
velocity and direction of the wind = 26.7 miles/hour at 20.8⁰
Explanation:
Let the velocities be resolved using the vector method.
Let the x - axis be directed to the east
similarly, we shall direct the y axis upwards- to the north
Airspeed is given by
300 mil/h. (30⁰) = 300 (cos30⁰i + sin 30⁰j
plane relative to ship
= 12 miles/hour
= 12j
- velocity of the plane is given by:
v =
+ Vijb
= -12 j + 280 (cos 33⁰i + sin 33⁰j)
= 234.83 i + 140.50 j
= 274 miles per hour
- velocity of the wind is given by the following equation:
= 234.831 + 140.50J - 300(cos 30⁰i + sin 30⁰j)
= -24.98i - 9.50 j
= 26.7 miles per hour at 20.8⁰
During World War ll, the United States and the Soviet Union fought together as the allies against the Axis power. However, the relationship between the two nations was a tense one. Americans had long been wary of Soviet communism and concerned about Russian leader Joseph Stalin’s tyrannical rule of his own country
Answer:
A dataflow architecture uses only concurrent signal assignment statements.
A behavioral architecture uses only process statements.
A structural architecture uses only component instantiation statements.
Usage
Dataflow modelling uses Boolean equations as design specifications. For eg. to design AND gate you use the equation y <= a & b ; Statements are executed concurrently. Behavioural modelling executes statements sequentially. They are written inside a process statement. Structural modelling uses logic diagrams.
Explanation:
The difference between these styles is based on the type of concurrent statements used:
Answer:
a) 0.2099
b) 46.5 MPa
c) 233765 N
d) 3896 W
Explanation:
a)
r = (A'' - A') / A'', where
A'' = 1/4 * π * D''²
A'' = 1/4 * 3.142 * 90²
A'' = 6362.55 mm²
D' = D'' - d = 90 - 10 = 80 mm
A' = 1/4 * π * D'²
A' = 1/4 * 3.142 * 80²
A' = 5027.2 mm²
r = (A'' - A') / A'
r = (6362.55 - 5027.2) / 6362.55
r = 1335 / 6362.55
r = 0.2099
b)
Draw stress = σd
Y' = k = 105 MPa
Φ = 0.88 + 0.12(D/Lc), where
D = 0.5 (90 + 80) = 85 mm
Lc = 0.5 [(90 - 80)/sin 18] = 16.18 mm
Φ = 0.88 + 0.12(85/16.18) = 1.51
σd = Y' * (1 + μ/tan α) * Φ * In(A''/A')
σd = 105 * (1 + 0.08/tan18) * 1.51 * In(6362.55/5027.2)
σd = 105 * 1.246 * 1.51 * 0.2355
σd = 46.5 MPa
c)
F = A' * σd
F = 5027.2 * 46.5
F = 233764.8 N
d)
P = 233764.8 (1 m/min)
P = 233764.8 Nm/min
P = 3896.08 Nm/s
P = 3896.08 W
Explanation:
There has been no information about related to which programming language is to be used, writing code algorithm.
Defining I/O's ;
Analogue output
A01, A02, A03,AO4
Analogue Input;
AI_1 // potentiometer input
// Based on controller used, assign channels to I/O's
// code
int voltage
Voltage = AI_1;
If (Voltage > 0 && Voltage < 1.25)
{
A01 = voltage
A02 = 0;
A03= 0
AO4= 0
}
If (Voltage > 1.25 && Voltage < 2.5)
{
A01 = 1.25
A02 = (Voltage -1.25);
A03= 0
AO4= 0
}
If (Voltage > 2.5 && Voltage < 3.75)
{
A01 = 1.25
A02 = 1.25
A03= (Voltage - 2.5);
AO4= 0
}
else
{
A01 = 1.25
A02 = 1.25
A03= 1.25
AO4= (Voltage - 3.75);
}
return
