Answer:
"1.4 mL" is the appropriate solution.
Explanation:
According to the question,
Now,
Increase in volume will be:
⇒ ![\Delta V = \alpha\times v_0\times \Delta \epsilon](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20%5Calpha%5Ctimes%20v_0%5Ctimes%20%5CDelta%20%5Cepsilon)
By putting the given values, we get
![=1.12\times 10^{-4}\times 500\times 25](https://tex.z-dn.net/?f=%3D1.12%5Ctimes%2010%5E%7B-4%7D%5Ctimes%20500%5Ctimes%2025)
![=1.12\times 10^{-4}\times 12500](https://tex.z-dn.net/?f=%3D1.12%5Ctimes%2010%5E%7B-4%7D%5Ctimes%2012500)
![=1.4 \ mL](https://tex.z-dn.net/?f=%3D1.4%20%20%5C%20mL)
Q=m(c∆t +heat of fusion + heat of evaporation)
m= 44g
c= 4.186 J/g.C
∆t= 107-(-8) =115 C
heat of fusion= 333.55 J/g
heat of evaporation=2260 J/g
Q=44(4.186*115 + 333.55 + 2260)
Q= 135297.36 J
Explanation:
Dehydrohalogenation reactions occurs as elimination reactions through the following mechanism:
Step 1: A strong base(usually KOH) removes a slightly acidic hydrogen proton from the alkyl halide.
Step 2: The electrons from the broken hydrogen‐carbon bond are attracted toward the slightly positive carbon (carbocation) atom attached to the chlorine atom. As these electrons approach the second carbon, the halogen atom breaks free.
However, elimination will be slower in the exit of Hydrogen atom at the C2 and C3 because of the steric hindrance by the methyl group.
Elimination of the hydrogen from the methyl group is easier.
Thus, the major product will A
Ground state means 1s which can hold 2 electrons.
l for 1s is = 0
ml = 0 (given)
possible values of m = 0
so it can hold maximum of 2 electrons. One spin up and other spin down.