Answer:
a scientific question
Procedure
Conclusion.
Explanation:
Scientific investigation is usually carried out to explain and give answers to natural phenomenon. Now, this scientific investigation is performed through the three main types as described in the question.
With that being said, the most common parts of all types of investigation are :
1. Scientific question: In this stage, questions are usually asked on the basis of observation made which could be answered.
2. Procedure: In this stage, the dimension of the steps are followed to answer and test the scientific question.
3. Conclusion: This is the primary aim that we check when done with our sample values
The enthalpy of the solution is <u>positive </u>and the entropy is <u>positive</u>.
Potassium trioxonitrate (V) KNO₃(s) is a strong oxidizing solid substance that when dissolved in water changes to aqueous solution.
In its aqueous solution state, the randomness of molecules increases as a result of that the entropy will also increase leading to the positive state of the entropy.
Similarly, provided that the solution becomes quite cold to the touch, the enthalpy is also in it positive state.
Therefore, we can conclude that the enthalpy of the solution is <u>positive </u>and the entropy is <u>positive</u>.
Learn more about Potassium trioxonitrate (V) KNO₃(s) here:
brainly.com/question/25303112
All pieces will be 17 g/cm^3 because the density is not affected by cutting (assuming the rock is uniform).
The wt% of KOH = 45%
This implies that there is 45 g of KOH in 100 g of the solution
Density of the solution is given as 1.45 g/ml
Therefore, the volume corresponding to 100 g of the solution is
= 100 g * 1 ml /1.45 g = 68.97 ml = 0.069 L
Now concentration of the concentrated KOH solution is:
Molarity = moles of KOH/vol of solution
= (45 g/56.105 g.mol-1)/0.069 L = 11.6 M
Thus,
Initial KOH concentration M1 = 11.6 M
Initial volume = V1
Final concentration M2 = 1.20 M
Final volume V2 = 250 ml
M1*V1= M2*V2
V1 = M2*V2/M1 = 1.20*250/11.6 = 25.9 ml = 26 ml
Answer:
60.88%
Explanation:
The <em>formula for cerium carbonate</em> is Ce₂(CO₃)₃.
Let's <u>assume we have 1 mol of cerium carbonate</u>. The total mass would be equal to the molar mass of Ce₂(CO₃)₃, 460.25 g/mol.
Out of those 460.25 g, the mass <u>corresponding to cerium would be</u>:
- 2 * Molar mass of Ce = 2 * 140.11 g/mol = 280.22 g
Now we can <u>calculate the percentage by mass of cerium</u>:
- % mass = 280.22 / 460.25 * 100% = 60.88%
