The arrangement in space and the interatomic distances and angles of the atoms in crystals, usually determined by x-ray diffraction measurements
Answer : Option E) 50 grams.
Explanation : According to the solubility curves the compound
to dissolve at 50 °C in 100 mL of water will need 50 grams of the compound. It is clearly indicated in the graph which is marked with red that at 50°C approximately 50.4 grams of the compound
will be needed to dissolved in 100 mL of water to form a solution.
The molecules will be more separated, and will have least amount of intermolecular force of attraction.
<h3><u>Explanation:</u></h3>
The molecules inside the jar of Lilly are moving around each other. This means the state of the matter present inside the jar is liquid. As Lily gives more energy inside the jar , the molecules inside the jar will get more separated as the kinetic energy of the molecules increase and the intermolecular force of attraction decreases as well as the intermolecular separation or distance increase. As the energy is continued to be supplied from outside, there will be a time when this liquid will reaches boiling point and will start to change into gas. After this point the intermolecular force of attraction will be least among molecules and their separation will be maximum.
Answer:
- [HOCl] = 0.00909 mol/liter
- [H₂O] = 0.03901 mol/liter
- [Cl₂O] = 0.02351 mol/liter
Explanation:
<u />
<u>1. Chemical reaction:</u>

<u>2. Initial concentrations:</u>
i) 1.3 g H₂O
- Number of moles = 1.3g / (18.015g/mol) = 0.07216 mol
- Molarity, M = 0.07216 mol / 1.5 liter = 0.0481 mol/liter
ii) 2.2 g Cl₂O
- Number of moles = 2.2 g/ (67.45 g/mol) = 0.0326 mol
- Molarity = 0.0326mol / 1.5 liter = 0.0217 mol/liter
<u>3. ICE (Initial, Change, Equilibrium) table</u>

I 0.0481 0.0326 0
C -x -x +x
E 0.0481-x 0.0326-x x
<u />
<u>4. Equilibrium expression</u>
![K_c=\dfrac{[HOCl]^2}{[H_2O].[Cl_2O]}](https://tex.z-dn.net/?f=K_c%3D%5Cdfrac%7B%5BHOCl%5D%5E2%7D%7B%5BH_2O%5D.%5BCl_2O%5D%7D)

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<u>5. Solve:</u>

Use the quadatic formula:

The positive result is x = 0.00909
Thus the concentrations are:
- [HOCl] = 0.00909 mol/liter
- [H₂O] = 0.0481 - 0.00909 = 0.03901 mol/liter
- [Cl₂O] = 0.0326 - 0.00909 = 0.02351 mol/liter