Answer:
CH2O
Explanation:
Firstly, we need to convert the masses of the elements to percentage compositions. This can be done by placing the mass of each element over the total mass multiplied by 100% . We can start with carbon.
C = 5.692/14.229 * 100 = 40%
O = 7.582/14.229 * 100 = 53.29%
H = 0.955/14.229 * 100 = 6.71%
We then proceed to divide each percentage composition by their atomic mass of 12, 16 and 1 respectively.
C = 40/12 = 3.333
O = 53.29/16 = 3.33
H = 6.71/2 = 6.71
Dividing by the smaller value which is 3.33
C = 3.33/3.33 = 1
O = 3.33/3.33= 1
H = 6.71/3.33 = 2
The empirical formula of the compound ribose is CH2O
Answer:
Can you please provide the elements?
Explanation:Attach a file or tyoe the names into the question
Answer:
See explanation below
Explanation:
First, let's write again the reaction:
CH₃COO⁻ + H(CH₃)₃N⁺ <-----------> CH₃COOH + (CH₃)₃N
Now that the reaction is here, let's remember the basis of the bronsted - lowry theory:
An acid (HA) is a substance that can lose a proton (Hydrogen atom) to form a conjugate base. A base is a substance that accepts the proton (Hydrogen) and form a conjugate acid.
According to this definition, let's see the reaction again.
In the reactants, we see the CH3COO and the H(CH3)N. and the products are CH3COOH and (CH3)3N. The difference? well, we can see that the CH3COO now has a Hydrogen atom, this means that the CH3COO accepted the Hydrogen; this hydrogen was provided by the H(CH3)3N.
Therefore, the acid in this reaction is the H(CH₃)₃N⁺ and the conjugate base will be the (CH₃)₃N
The base in this reaction is the CH₃COO⁻ while the conjugate acid will be the CH₃COOH
