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djyliett [7]
3 years ago
15

HELP!!!

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
5 0

Answer: with dog figs- it is 590

With decimals it is 589.68

Explanation:

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What word is used to describe the electrodes used in electrolysis that do not react?
Klio2033 [76]

Answer:

Electrodes are the rods that carry the electric current to and from the electrolyte. These rods are usually inert, as in they do not react- usually graphite or platinum. The positive electrode is called the anode and the negative electrode is called the cathode.

Explanation:

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3 years ago
Which of the following is a chemical property of the noble gases?
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Noble gases are the elements located in the eighth group of the periodic table. These elements have the following properties:
They are odorless
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They are colorless
They have very low chemical reactivity

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5 0
3 years ago
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Explain the difference between a front and an air mass.
iVinArrow [24]

Answer: The differences is Air masses cover over thousands and hundreds and millions of square kilo. A front is a boundary which two air masses but different temperature and moisture content meet.

Explanation:

8 0
3 years ago
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suter [353]

Answer:

I think it is 100 if I guess

8 0
3 years ago
If a particular ore contains 58.6 % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg of phosp
rjkz [21]
Answer is: mass of the ore is 8.54kg.<span>

</span>ω(Ca₃(PO₄)₂ - calcium phosphate) = 58.6% ÷ 100% = 0.586.
m(P) = 1.00 kg · 1000 g/kg.
m(P) = 1000 g.
In one molecule of calcium phosphate there are two phosphorus atoms:
M(Ca₃(PO₄)₂) = 310.18 g/mol.
M(P) = 30.97 g/mol.
For one kilogram of phosphorus, we need:
M(Ca₃(PO₄)₂) : 2M(P) = m(Ca₃(PO₄)₂) : m(P).
310.18 g/mol : 61.94 g/mol = m(Ca₃(PO₄)₂) : 1000 g.
m(Ca₃(PO₄)₂) = 5007.75 g ÷ 1000 g/kg = 5.007 kg.
Mass of ore find from proportion:
m(Ca₃(PO₄)₂) : m(ore) = 56% : 100%.
m(ore) = 100% · 5.007 kg ÷ 58.6%.
m(ore) = 8.54kg.

5 0
3 years ago
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