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lana [24]
3 years ago
14

How many electrons would be found in the ion whose symbol is given below ? N3-

Chemistry
1 answer:
Anna [14]3 years ago
6 0

Answer:

N³⁻ contain  seven protons and ten electrons.

Explanation:

Nitrogen have seven protons and seven electrons. When it an atom lose or gain the electrons ions are formed.

Cation:

When an atom lose the electrons the formed is called cation.

e.g Na⁺ sodium lose one electron and form cation.

Anion:

when an atom gain the electrons the ions formed is called anion.

e.g N³⁻

Nitrogen consist of seven electrons and seven protons. when it gain electrons anions are formed. In given symbol nitrogen consist of 3- charge which means nitrogen gain three more electrons so total electrons will be ten.

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A compound is formed when 12.2 g Mg combines completely with 5.16 g N. What is the percent composition of this compound? Please
STALIN [3.7K]
3Mg + N₂= Mg₃N₂
n(Mg)=12,2g÷<span>24,4g/mol=0,5mol-limiting reagent
</span>n(N₂)=5,16g÷28g/mol=0,18mol
n(Mg₃N₂):n(Mg)=1:3, n(Mg₃N₂)=0,166mol, m(Mg₃N₂)=0,166·101,2=16,8g.
%(N)= 2·Ar(N)÷Mr(Mg₃N₂) = 2·14÷101,2=27,66%=0,2766
%(Mg) = 3·Ar(Mg)÷Mr(Mg₃N₂)= 3·24,4÷101,2=72,34% or 100% - 27,66%= 72,34%.
4 0
3 years ago
Which of these metals reacts more vigorously with water? <br><br> 1. Zinc <br> 2. Magnesium
GalinKa [24]

Answer:

magnesium  

Explanation:

because zinc does not react with water because it too forms a protective layer of insoluble.

8 0
2 years ago
A compound's properties are different than the properties of the elements that make it up.
yan [13]
The answer is True because elements in a compound combine and become an entirely different substance with its own unique properties.
7 0
3 years ago
Cyclopropene decomposes to propene when heated to 500 C, calculate rate constant for the first order reaction 0 min 1.48 mmol/L
Dmitry_Shevchenko [17]

Answer:

k = 0.0306 min-1

Explanation:

The table is given as;

Time, Concentration

0 1.48

5 1.27

10 0.98

15 0.84

The integrated rate law for a first order reaction is given as;

ln [A] = -kt + ln [Ao]

where;

[A] = Final Concentration

[Ao] = Initial Concentration

k = rate constant

t = time

In the table, taking the first two sets of values;

t = 5

k = ?

[Ao]  = 1.48

[A] = 1.27

Inserting into the equation;

ln(1.27) = - k (5) + ln(1.48)

ln(1.27)  - ln(1.48) = -5k

-0.1530 = -5k

k = -0.1530 / -5

k = 0.0306 min-1

6 0
3 years ago
What caused the bubbles to form when you added the catalase to the hydrogen peroxide and water mixture at 40 °c?
Dahasolnce [82]
<span>What caused the bubbles to form when you added the catalyses to the hydrogen peroxide and water mixture at 40 °C? A. Catalyses activity heated the solution to its boiling point. B. Hydrogen gas formed during the formation of hydrogen peroxide. C. Oxygen gas formed during the decomposition of hydrogen peroxide.

This would be the water, mixture.</span>
7 0
3 years ago
Read 2 more answers
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