Nitrogen have seven protons and seven electrons. When it an atom lose or gain the electrons ions are formed.
Cation:
When an atom lose the electrons the formed is called cation.
e.g Na⁺ sodium lose one electron and form cation.
Anion:
when an atom gain the electrons the ions formed is called anion.
e.g N³⁻
Nitrogen consist of seven electrons and seven protons. when it gain electrons anions are formed. In given symbol nitrogen consist of 3- charge which means nitrogen gain three more electrons so total electrons will be ten.
to neutralize 1 mole of H2 S o4 we need one mole of any if we are having 50 grams of H2 S o4 it means the mole of H2 S o4 in 50 gram will be 50×40)/98 hence
utilising 50 grams of H2 S o4 we need approximately 20. 5 gm of Naoh
We consider the given reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O as applies to an acid-base titration. moles NaOH = c · V = 0.2767 mmol/mL · 25.34 mL = 7.011578 mmol moles H2SO4 = 7.011578 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.505789 mmol Hence [H2SO4]= n/V = 3.505789 mmol / 39.54 mL = 0.08866 M The answer to this question is [H2SO4] = 0.08866 M
