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labwork [276]
3 years ago
7

G problem 2.68 determine the magnitude of the resultant force.

Physics
1 answer:
laila [671]3 years ago
7 0
Abbs as sbsbbbdb sbsb
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Give you point but please i need help in physcis
Anastasy [175]

Explanation:

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7 0
3 years ago
A 2.0-kg ball rolls to the right at 3.0 m/s. A 4.0-kg ball rolls to the left at 2.0 m/s . What is the momentum of the system aft
charle [14.2K]

Answer:

Final momentum after a head on collision is -2kgm/s

Explanation:

         One ball moves to the right and the other moves opposite  and momentum is a vector quantity so that considering the direction

Initial momenta are        P₁=2x3=6kgm/s        P₂=4x(-2)=-8kgm/s      

Final momentum is the vector sum of P(final)= 6-8= -2 kgm/s

4 0
3 years ago
A convex lens has a focal length of 16.5 cm. Where on the lens axis should an object be placed in order to get a virtual, enlarg
alexandr402 [8]

Answer:

Object should be placed at a distance, u = 7.8 cm

Given:

focal length of convex lens, F = 16.5 cm

magnification, m = 1.90

Solution:

Magnification of lens, m = -\frac{v}{u}

where

u = object distance

v = image distance

Now,

1.90 = \frac{v}{u}

v = - 1.90u

To calculate the object distance, u by lens maker formula given by:

\frac{1}{F} = \frac{1}{u}+ \frac{1}{v}

\frac{1}{16.5} = \frac{1}{u}+ \frac{1}{- 1.90u}

\frac{1}{16.5} = \frac{1.90 - 1}{1.90u}

\frac{1}{16.5} = \frac{ 0.90}{1.90u}

u = 7.8 cm

Object should be placed at a distance of 7.8 cm on the axis of the lens to get virtual and enlarged image.

6 0
4 years ago
An object moves 2.5 m. This is an example of a _______. Question 3 options: direction distance velocity speed
Hitman42 [59]
Distance, since distance represents how far something has travelled, which would be in our case 2.5m.
5 0
3 years ago
Read 2 more answers
What if an object traveled from position -6 m to -1 m, what is the distance traveled?
Oxana [17]
The object traveled +5 m
4 0
3 years ago
Read 2 more answers
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