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labwork [276]
3 years ago
7

G problem 2.68 determine the magnitude of the resultant force.

Physics
1 answer:
laila [671]3 years ago
7 0
Abbs as sbsbbbdb sbsb
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Which statement best summarizes the central idea of “Applications of Newton’s Laws”?
Shkiper50 [21]

 

Newton's three forces, normal, tension and friction, are present in a surprising number of physical situations

Newton's Laws, that describe the relationship between an obejct and the forces acting upon it, apply in almost every physical situation, from quantum mechanics to electricity.

The correct answer is:

Newton’s laws can explain the forces that occur between objects every day


3 0
3 years ago
Read 2 more answers
Why is a star an example of a good blackbody radiator?
Anna11 [10]

Answer: A. It gives off a range of wavelengths of electromagnetic radiation that depends on its temperature.

Explanation: Quizzed

4 0
2 years ago
If an object is dropped from a height of meters, the velocity (in ) at impact is given by v= √2gh , where g=9.8m/sec^2 is the ac
Neporo4naja [7]

Answer:

A.) V = 14 m/s

B.) h = 36.6 m

Explanation:

Given the formula v = √2gh

where g = 9.8m/sec^2 is the acceleration due to gravity.

A.) Determine the impact velocity for an object dropped from a height of 10 m.

Substitute height h in the given formula

V = √2gh 

V = √2 × 9.8 × 10

V = √196

V = 14 m/s

b. Determine the height required for an object to have an impact velocity of 26.8 m/sec (~ 60 mph). Round to the nearest tenth of a meter.

Substitute the velocity in the given formula and make height h the subject of formula.

26.8 = √2 × 9.8 × h

Square both sides

718.24 = 19.6h

h = 718.24 / 19.6

h = 36.64 m

h = 36.6 m

5 0
3 years ago
A mover hoists a 200 kg piano from the ground to a height of 10 m using a single pulley. What was the change in the pianos energ
RideAnS [48]
P.E= Mass x gravity x height   (standard gravity = 10m/s approaximately)
     = 200x10x10= 20000j (D)
7 0
3 years ago
Read 2 more answers
580 nm light shines on a double slit
Helga [31]

Answer:

0.532

Explanation:

Your equation to find the second bright interference maximum is gonna be this: d sin (Θ) = m λ

First, find your variables.

λ = 580 · 10^-9

d = 0.000125

m = 2

Next, fill in the equation.

d sin (θ) = m λ

(0.000125) sin (θ) = (2) (580·10^-9)

Then isolate your variable.

θ = arcsin ( (2)(580·10^-9) / (0.000125) )

Run your equation and you will end up with 0.53171246 , which rounds to 0.532.

The main thing you have to watch out for is make sure you are calculating for the bright interference and not the dark interference, as well as checking you're calculating for the maximum, not the minimum.

I hope this helps :D

5 0
3 years ago
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