Heat released : 79086 J
<h3>Further explanation</h3>
Condenses :
1. phase change (gas - liquid) : heat of vaporization (ΔH vap for water = 2260 J/g)
2. cools from 100 - 10 : (Q=m.cΔT)
1. Q=m.ΔH vap
2. Q=mc.ΔT(c water = 4.18 J/g C)
Q tot = 67800 + 11286 = 79086 J
Answer:
you are correct good luck
Answer is: key
design change for HFC-134a A/C systems versus CFC-12 A/C systems was quick
couple service fitting and that design reduce venting and mixing of
refrigerants during service.
<span>
Level of contamination is also reduced
and the emission of refrigerants and greenhouse gases (sulfur
dioxide, carbon dioxide) is also reduced.</span>
Answer:
The answer to your question is V2 = 3.7 L
Explanation:
Data
Volume 1 = 3.5 L
Temperature 1 = 25°C
Temperature 2 = 40°C
Pressure = cte.
Volume 2 = ?
Formula
To solve this problem use the Charles' law
V1/T1 = V2/T2
- Solve for V2
V2 = V1T2 / T1
- Convert temperature to °K
Temperature 1 = 25 + 273 = 298°K
Temperature 2 = 40 + 273 = 313°K
- Substitution
V2 = (3.5)(313) / 298
- Simplification
V2 = 1095.5 / 298
- Result
V2 = 3.7 L
Answer:
Explanation:
Hello there!
In this case, since the heat of fusion is a property that allows us to calculate the heat involved during the change from solid to liquid (fusion) and is calculated as shown below:
In such a way, given the heat involved during this process and the mass of copper, we calculate the heat of fusion as shown below:
Or in kJ/mol:
Regards!