Answer:
Products will be K2SO4 and Cu(NO3)2. A precipitate will not form.
Explanation:
Double replacement reactions are the switching of cations between two compounds. So in this case, the K+ and Cu 2+ cations will switch places.
KNO3 + CuSO4 -> K2SO4 + Cu(NO3)2
According to solubility rules, any substances containing NO3 or a Group 1 ion (K+ in this case) will be definitely soluble. There are a few exceptions to the Group 1 rule but it does not apply here. Potassium sulfate (K2SO4) contains a Group 1 ion so it will be soluble and not be a precipitate. And copper nitrate (Cu(NO3)2) contains nitrate so it will also be soluble and not be a precipitate.
Correct answer choice is :
B) Chemistry
Explanation:
Advanced titanium-based compounds have been also used for some years for extremely stressed femoral segment stalks. Both metal samples present a higher impedance to pitting, crack, and galvanic corrosion, stress corrosion weakening and corrosion burnout than polished stainless steel of comparatively low power properties. For this purpose, the low element power of hip prostheses made of the recent stuff is paid for by a larger cross-section of the prosthetic stem, this depending on the geometric situations of the femur.
Hey there!
Molar mass Na2SO4 = 142.04 g/mol
Number of moles:
n = m / mm
n = 25 / 142.04
n = 0.176 moles of Na2SO4
Therefore, use the Avogadro constant
1 mole Na2SO4 ------------------- 6.02x10²³ molecules
0.176 moles Na2SO4 ------------ molecules ??
0.176 x ( 6.02x10²³ ) / 1
=> 1.059x10²³ molecules of Na2SO4
hope this helps!
Answer:
[OH-] = 6.17 *10^-10
Explanation:
Step 1: Data given
pOH = 9.21
Step 2: Calculate [OH-]
pOH = -log [OH-] = 9.21
[OH-] = 10^-9.21
[OH-] = 6.17 *10^-10
Step 3: Check if it's correct
pOH + pH = 14
[H+]*[OH-] = 10^-14
pH = 14 - 9.21 = 4.79
[H+] = 10^-4.79
[H+] = 1.62 *10^-5
6.17 * 10^-10 * 1.62 * 10^-5 = 1* 10^-14
Answer:
Because sodium is on the left side of the PT and phosporus is on the right side. And atomis radius decreases from left to right.
Explanation: