Answer: M= 128 g/mol (Te is quite close)
Explanation: number of Oxygen moles is n = 8 g / 32 g/mol = 0,25 mol.
Because formula of oxide is MO, thus amount of metal is also 0,25 mol.
Because n = m/M , Molar mass of the metal M = m/n = 32 g /0.25 mol = 128 g/ mol
Answer:
C. some substances can move freely across the cell membrane, while others must be transported.
Explanation:
Answer:

Explanation:
Hello!
In this case, since the formula for the calculation of molarity is:

Whereas we can compute the moles of the solute as shown below, making sure the volume is in liters:

Thus, by plugging in we obtain:

Next, since the molar mass of NaCl is 58.44 g/mol, we obtain the following mass:

Best regards!
Answer:
The molarity of HCl is 0.138 M
Explanation:
The titration reaction is as follows:
2HCl + Ca(OH)₂ → CaCl₂ + 2H₂O
When no more HCl is left, the small excess of Ca(OH)₂ added will cause the pH to rise and the indicator will turn. At this point, the number of moles of Ca(OH)₂ added will be the same as half the number of moles of HCl since 1 mol Ca(OH)₂ reacts with 2 moles HCl. Then:
At the endpoint:
moles Ca(OH)₂ = moles HCl / 2
Knowing the number of moles of Ca(OH)₂ added, we can calculate the number of moles of the acid:
mol Ca(OH)₂ = Volume added * concentration of Ca(OH)₂
mol Ca(OH)₂ = 0.0265 l * 0.130 mol/l = 3.45 x 10⁻³ mol Ca(OH)₂
The number of moles of HCl will be:
mol HCl = 2 * 3.45 x 10⁻³ mol = 6.89 x 10⁻³ mol HCl
This number of moles was present in 50.0 ml, then, in 1000 ml:
mol of HCl in 1000 ml = 6.89 x 10⁻³ mol HCl * (1000ml / 50ml) = 0.138 mol
Then:
Molarity HCl = 0.138 M