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MissTica
3 years ago
14

The graph of a sinusoidal function intersects its midline at (0,2) and then has a minimum point at (3,-6) Write the formula of t

he function, where x is entered in radians.
Mathematics
1 answer:
Dominik [7]3 years ago
4 0

Answer:  y = -8sin(1/3)π x + 2

<u>Step-by-step explanation:</u>

The equation of a cosine function is:    y = A cos(Bx - C) + D    where

  • Amplitude (A) is the distance from the midline to the max (or min)
  • Period (P) is the length of one cosine wave   -->   P = 2π/B
  • Phase Shift (C/B) is the horizontal distance shifted from the y-axis
  • Midline (D) is the vertical shift. It is equal distance from the max and min

<u>Midline (D) = 2</u>

(0, 2) is given as a point on the midline.  We only need the y-value.

<u>Horizontal stretch (B) = (1/3)π</u>

The min is located at (3,-6) --> x = 3  which is half of the Period.  Thus the period (length of one wave) is 3·2 = 6 units.

P=\dfrac{2\pi}{B}\qquad \rightarrow \qquad 6=\dfrac{2\pi}{B}\qquad \rightarrow \qquad B=\dfrac{2}{6}\pi\qquad \rightarrow B=\dfrac{1}{3}\pi          

<u>Phase Shift (C) = 0</u>

The midline is on the y-axis so there is no horizontal shift.

<u>Amplitude (A) = 7</u>

The distance from the min to the midline is: A = -6 - 2 = -8

<u>Equation</u>

Input A = -8, B = (1/3)π, C = 0, and D = 2 into the sine equation.

            y = A sin(Bx - C) + D

            y = -8sin((1/3)π x - 0) + 2

            y = -8sin(1/3)π x + 2

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