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34kurt
3 years ago
9

If a person pulls back a rubber band on a slingshot without letting to go of it, what type of energy will the rubber band have?

A. Potential energy B. Rotational energy C. Kinetic energy D. Translational energy
Physics
1 answer:
Travka [436]3 years ago
7 0

Answer:

Potential energy. Releasing it, the potential energy would convert into motion, kinetic energy.

Potential energy is when an object has some sort of potential eg. for motion such as in this example.

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A toy car on a string is pulled across a table horizontally. The string is at an
svlad2 [7]

(C)

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5 0
3 years ago
A positively charged particle is moving toward the South in a region of space where there is a magnetic field directed down (tow
Alexxandr [17]

Answer:

F = Q V X B

V = south

B = down

V X B = east

8 0
2 years ago
The position function x (6.0 m) cos[(3p rad/s)t p/3 rad]gives the simple harmonic motionof a body. at t 2.0 s, what are the(a) d
Daniel [21]

The correct formula for this simple harmonic motion is:

x = (6.0) cos [ (3 pi) t + pi/3 ] 

 

A. Calculating for displacement x at t = 2:

x =6.0 cos (19/3 pi)
x = 6 (0.5)

x = 3 m

 

<span>B. Velocity is equivalent to the 1st derivative of the equation. v = dx / dt </span>

<span> Velocity v = dx/dt = -18 pi sin (3pi t + pi/3) </span>

v = - 18 pi sin (6pi + pi/3)

v = 49.0 m/s

 

<span>C. Acceleration is the 2nd derivative or the 1st derivative of velocity dv / dt</span>
Acceleration a = dv/dt = -54 pi^2 cos(3pi t + pi/3) 

a = -54 pi^2 cos(3pi * 2 + pi/3)

a = 386.34 m/s^2

D. Phase = pi/3 

E. frequency f= 3pi/2pi = 1.5Hz 


<span>F. period = 1/f = 1/1.5 = .6667sec </span>

5 0
4 years ago
Calculate specific heat of liquid if a 450. g iron block is heated to 98.0 C and then droped into a calorimeter with 125 g of un
Naya [18.7K]

Answer:

Specific heat of liquid 1.258 \ J/g^0C.

Explanation:

We know in thermal equilibrium :

Loss in heat by iron block = Gain in heat by liquid .

Specific heat of iron = 0.45 J/g^0C.  { source internet }

Now , loss in heat by iron block = mC_{iron}\Delta T=450\times 0.45\times 57.6=11664\ J.

Heat gain by liquid=mC_{liquid}\Delta T=450\times C_{liquid}\times 20.6=9270\times C_{liquid}.

Equating both we get :

C_{liquid}=1.258 \ J/g^0C.

7 0
3 years ago
Scientific inquiry includes many different activities. Which of the following is a process that is typically performed during a
Juli2301 [7.4K]
D. All of these, they’re all part of scientific inquiry
7 0
3 years ago
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