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ExtremeBDS [4]
3 years ago
6

Intro to Springs and Hooke’s law

Physics
1 answer:
wel3 years ago
6 0
A spring is an object that can be deformed by a force and then return to its original shape after the force is removed.
Springs come in a huge variety of different forms, but the simple metal coil spring is probably the most familiar. Springs are an essential part of almost all moderately complex mechanical devices; from ball-point pens to racing car engines.
There is nothing particularly magical about the shape of a coil spring that makes it behave like a spring. The 'springiness', or more correctly, the elasticity is a fundamental property of the wire that the spring is made from. A long straight metal wire also has the ability to ‘spring back’ following a stretching or twisting action. Winding the wire into a spring just allows us to exploit the properties of a long piece of wire in a small space. This is much more convenient for building mechanical devices.
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A child wants to pump up a bicycle tire so that its pressure is 1.2 × 105 pa above that of atmospheric pressure. if the child us
WINSTONCH [101]
General expression is;
Pressure = Force/Area
In which,
Pressure = Required pressure + Atmospheric pressure = (1.2*10^5) + (101325) = 221325 Pa = 221325 N/m^2

Area = πD^2/4 = π*0.035^2/4 = 9.621*10^-4 m^2

Therefore,
Force, F = Pressure*Area = 221325*9.621*10^-4 = 212.94 N
7 0
3 years ago
Read 2 more answers
Assume you push a 20 kg child in a little red wagon with a force of 100 N. However, the dirt and rocks below the wheels
GenaCL600 [577]

Answer:

a

Explanation:

4 0
3 years ago
With what speed does the can move immediately after the collision? Answer in units of m/s.
Ratling [72]

Answer:

1.74 m/s

Explanation:

From the question, we are given that the mass of the an object, m1= 2.7 kilogram(kg) and the mass of the can,m(can) is 0.72 Kilogram (kg). The velocity of the mass of an object(m1) , V1 is 1.1 metre per seconds(m/s) and the velocity of the mass of can[m(can)], V(can) is unknown- this is what we are to find.

Therefore, using the formula below, we can calculate the speed of the can, V(can);

===> Mass of object,m1 × velocity of object, V1 = mass of the can[m(can)] × velocity is of the can[V(can)].----------------------------------------------------(1).

Since the question says the collision was elastic, we use the formula below

Slotting in the given values into the equation (1) above, we have;

1/2×M1×V^2(initial velocity of the first object) + 1/2 ×M(can)×V^2(final velocy of the first object)= 1/2 × M1 × V^2 m( initial velocity of the first object).

Therefore, final velocity of the can= 2M1V1/M1+M2.

==> 2×2.7×1.1/ 2.7 + 0.72.

The velocity of the can after collision = 1.74 m/s

7 0
3 years ago
A 26.0-kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 225 N. For the first 11.0 m th
frozen [14]

Answer:

18 m/s

Explanation:

Force is given by mass × acceleration

<em>F = ma</em>

<em>a = F/m</em>

For the first 11.0 m, there is no friction. Hence, the constant force is applied fully on the crate. The acceleration is

<em>a = </em>225/26.0<em> </em>m/s²

By the equation of motion, <em>v² = u² + 2as</em>

where <em>v</em> is the final velocity, <em>u</em> is the initial velocity, <em>a</em> is the acceleration and <em>s</em> is the distance travelled.

Using the values for the first part of the motion,

<em>v² = </em>0² + 2 × 8.65 × 11.0

<em>v = </em>13.8 m/s

This is the initial velocity for the second part of the motion. This part has friction of coefficient 0.20.

The frictional force = 0.20 × weight = 0.20 × 26.0 × 9.8 = 50.96 N

The effective force moving the crate in the second motion = 225 - 50.96 N = 174.04 N

This gives an acceleration of 174.04/26.0 = 6.69 m/s².

Using parameters for the equation of motion, <em>v² = u² + 2as</em>

<em>v² = </em>13.8² + 2 × 6.69 × 10 = 324.24

<em>v = </em>18<em> </em>m/s

8 0
4 years ago
It takes 120 minutes for a man to ride his bicycle up the road to Alpe d'Huez in France. The vertical height of the climb is 1,1
Greeley [361]
First solve the potential energy of the biker. using the fomula:
PE = mgh
where m  is the mass of the object
g is the acceleration due to gravity ( 9.81 m/s2)
h is the height

PE = 96 kg ( 1120 m ) ( 9.81 m/s2)
PE = 1054771.2 J
then power = Work / time
P = 1054771.2 J / ( 120 min ) ( 60 s / 1 min)
P = 146.5 W

8 0
4 years ago
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