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Liono4ka [1.6K]
3 years ago
11

You're in the middle of moving and need to bring furniture and into your new house. You want to prop the door open, but your dog

ate the doorstopper (and your homework). All you can find is a large brick. If you want to impart the largest torque on the door to keep it open, where should you place the brick?
A) Put the brick as close to the hinges as possible.
B) Put the brick in the middle of the door.
C) Put the brick as far from the hinges as possible.
Physics
1 answer:
Mamont248 [21]3 years ago
3 0

Answer:

C) Put the brick as far from the hinges as possible

Explanation:

As torque is the product of the force around the rotation point and the distance to the pivot point, and the mass (force) of the brick stays constant, what we can do to maximize the torque is maximize the distance to the pivot point, aka the hinge. So we should put the brick as far from the hinges as possible.

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A car is moving at a constant speed of 100 miles per hour. how long does it take for the car to travel 200 miles.
Pepsi [2]

Answer:

d. 2 hours

Explanation:

because if it travels 100 miles per hour in 1 hour it would travel 200 miles in 2 hours and so fourth.

4 0
2 years ago
Using the right amount of significant figures, calculate the answer to the following problem, 215.5+101.02555
cestrela7 [59]

Answer:

This is how I figured it out:

  1. 215.5 rounded to one significant figure is 200
  2. 101.02555 rounded to one significant figure is 100.
  3. 200 + 100 = 300.

Hope this helps!

Explanation:

7 0
3 years ago
An ultrasonic tape measure uses frequencies above 20 MHz todetermine dimensions of structures such as buildings. It does so byem
ohaa [14]

Answer:  

a) 1m

b) 2μs

c) 3mm

Explanation:

3 0
3 years ago
Lucia kicks a ball on a level playing field with an initial velocity of 11.3 m/s at an angle of 35° above the horizontal. Find:
grandymaker [24]

Explanation:

Given that,

Initial velocity, u = 11.3 m/s

Angle above the horizontal, \theta=35^{\circ}

Time of flight :

t=\dfrac{2u\sin\theta}{g}\\\\t=\dfrac{2\times 11.3\times \sin(35)}{9.8}\\\\t=1.32\ s

Horizontal distance traveled  is given by :

x = ut

x = 11.3 m/s × 1.32 s

x = 14.916 m

Maximum height is given by :

H=\dfrac{u^2\sin^2\theta}{2g}\\\\H=\dfrac{(11.3)^2\times \sin^2(35)}{2\times 9.8}\\\\H=2.14\ m

Hence, time of flight is 1.32 s, horizontal distance is 14.916 m and maximum height is 2.14 m.

6 0
2 years ago
A man releases a stone ar the top edge of a tower during the last second of its travel the stone falls through a distance of (9/
Musya8 [376]
Equations of motion (EoM) use EoM <span>v2=u2+2ax</span> to establish velocities at positions shown in blue in drawing from EoM v=u+at for final 1 second of flight time, we can say v=u+g(1) <span><span>2gH−−−−√</span>=<span><span>2g1625H</span>−−−−−−√</span>+g</span><span> then, solve for H [in terms of g]

</span>
4 0
3 years ago
Read 2 more answers
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