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neonofarm [45]
3 years ago
8

A box is sliding up an inclined plane with friction, and it is speeding up.What free-body diagrams matches this description?

Physics
1 answer:
sukhopar [10]3 years ago
6 0

Answer: photo

Explanation: because

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Concrete is pumped from a cement mixer to the place it is being laid, instead of being carried in wheelbarrows. The flow rate is
max2010maxim [7]

Answer:

a. 2.4 ×109  N ⋅ m2/s

b. 48.3 N⋅s /m2  

c. 8.00×104W

Explanation:

See Attached file for explanation

3 0
3 years ago
Find deacceleration An engineer in a locomotive sees a car stuck on the track at a railroad crossing in front of the train. When
earnstyle [38]

Answer:

The deceleration is  a = -0.7273 \ m/s^2  

Explanation:

From the question we are told that

  The distance of the car from the crossing is d = 360 \  m

   The speed is u  = 16 \  m/s

    The reaction time of the engineer is  t = 0.53 \ s

Generally the distance covered during the reaction time is  

      d_r = u * t

=>   d_r = 16 * 0.53

=>   d_r = 8.48 \ m

Generally distance of the car from the crossing after the  engineer reacts is

      D = d- d_r        

=> D = 360 - 8.48      

=> D = 352 \ m

Generally from kinematic equation

      v^2 = u^2 + 2as

Here v is the final velocity of the car which is  0 m/s

So

        0^2 = 16^2 + 2 * a * 352

=>    a = -0.7273 \ m/s^2  

3 0
2 years ago
Which two events are part of the rock cycle?
kozerog [31]

Answer:

B and C

Explanation:

I got it right on my a pex test

8 0
2 years ago
A long solenoid has a radius of 2.0 cm and has 700 turns/m. If the current in the solenoid is decreasing at the rate of 8.0 A/s,
Brrunno [24]

Answer:

The magnitude of the induced electric field at a point 2.5 cm from the axis of the solenoid is 8.8 x 10⁻⁵ V/m

Explanation:

given information:

radius, r = 2.0 cm

N = 700 turns/m

decreasing rate, dI/dt = 9.0 A/s

the magnitude of the induced electric field at a point 2.5 cm (r = 2.5 cm = 0.025 m) from the axis of the solenoid?

the magnetic field at the center of solenoid

B = μ₀nI

where

B = magnetic field (T)

μ₀ = permeability (1.26× 10⁻⁶ T.m/A)

n = the number turn per unit length (turn/m)

I = current (A)

dB/dt = μ₀n dI/dt                                           (1)

now we calculate the induced electric field by using

E = \frac{1}{2}r\frac{dB}{dt}  

\frac{dB}{dt} = 2E/r                                                     (2)

where

E = the induced electric field (V/m)

we substitute the firs and second equation, thus

dB/dt = μ₀n dI/dt  

2E/r = μ₀n dI/dt  

E = (1/2) r μ₀n dI/dt

  = (1/2) (0.025) (1.26× 10⁻⁶) (700) (8)

  = 8.8 x 10⁻⁵ V/m

6 0
3 years ago
A coin is placed 10.8 cm from the axis of a rotating turntable of variable speed. When the speed of the turntable is slowly incr
Advocard [28]

Answer:

Coefficient of static friction = 0.547

Explanation:

The maximum resistive force offered by the body(coin)against the applied force(turntable) to continue its state of motion is called Coefficient Of Static Friction

When given

The angular velocity which is 51.1rpm

We are going to calculate velocity of coin

= r*w(angular velocity) = 0.108*(51.1*2π/60) = 0.58

Coefficient=F/N

F= coefficient* N = coefficient*m*g

F= mv^2/r which is centripetal force

Therefore, mv^2/r = coefficient*m*g

coefficient = mv^2/mgr = v^2/rg

Where g,gravity = 9.81

Substitute into the equation coefficient = 0.58^2/9.81*0.108

= 0.547

7 0
3 years ago
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