Answer:
a. 2.4 ×109 N ⋅ m2/s
b. 48.3 N⋅s /m2
c. 8.00×104W
Explanation:
See Attached file for explanation
Answer:
The deceleration is
Explanation:
From the question we are told that
The distance of the car from the crossing is 
The speed is 
The reaction time of the engineer is 
Generally the distance covered during the reaction time is

=> 
=> 
Generally distance of the car from the crossing after the engineer reacts is
=>
=> 
Generally from kinematic equation

Here v is the final velocity of the car which is 0 m/s
So

=>
Answer:
B and C
Explanation:
I got it right on my a pex test
Answer:
The magnitude of the induced electric field at a point 2.5 cm from the axis of the solenoid is 8.8 x 10⁻⁵ V/m
Explanation:
given information:
radius, r = 2.0 cm
N = 700 turns/m
decreasing rate, dI/dt = 9.0 A/s
the magnitude of the induced electric field at a point 2.5 cm (r = 2.5 cm = 0.025 m) from the axis of the solenoid?
the magnetic field at the center of solenoid
B = μ₀nI
where
B = magnetic field (T)
μ₀ = permeability (1.26× 10⁻⁶ T.m/A)
n = the number turn per unit length (turn/m)
I = current (A)
dB/dt = μ₀n dI/dt (1)
now we calculate the induced electric field by using
E =
= 2E/r (2)
where
E = the induced electric field (V/m)
we substitute the firs and second equation, thus
dB/dt = μ₀n dI/dt
2E/r = μ₀n dI/dt
E = (1/2) r μ₀n dI/dt
= (1/2) (0.025) (1.26× 10⁻⁶) (700) (8)
= 8.8 x 10⁻⁵ V/m
Answer:
Coefficient of static friction = 0.547
Explanation:
The maximum resistive force offered by the body(coin)against the applied force(turntable) to continue its state of motion is called Coefficient Of Static Friction
When given
The angular velocity which is 51.1rpm
We are going to calculate velocity of coin
= r*w(angular velocity) = 0.108*(51.1*2π/60) = 0.58
Coefficient=F/N
F= coefficient* N = coefficient*m*g
F= mv^2/r which is centripetal force
Therefore, mv^2/r = coefficient*m*g
coefficient = mv^2/mgr = v^2/rg
Where g,gravity = 9.81
Substitute into the equation coefficient = 0.58^2/9.81*0.108
= 0.547