Answer:
Explanation:
The answer is B.
B) C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(g)
The velocity of an electron that has been accelerated through a difference of potential of 100 volts will be 5.93 * m/s
Electrons move because they get pushed by some external force. There are several energy sources that can force electrons to move. Voltage is the amount of push or pressure that is being applied to the electrons.
By conservation of energy, the kinetic energy has to equal the change in potential energy, so KE=q*V. The energy of the electron in electron-volts is numerically the same as the voltage between the plates.
given
charge of electron = 1.6 × C
mass of electron = 9.1 × kg
Force in an electric field = q*E
potential energy is stored in the form of work done
potential energy = work done = Force * displacement
= q * (E * d)
= q * (V) = 1.6 × * 100
stored potential energy = kinetic energy in electric field
kinetic energy = 1/2 * m *
= 1/2 * 9.1 × *
equation both the equations
1/2 * 9.1 × * = 1.6 ×
= 0.352 * m/s
= 35.2 *
= 5.93 * m/s
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Answer:
Charge Z can be placed at <em>x</em> = -2.7 m or at <em>x</em> = 0.27 m.
Explanation:
The Coulomb force between two charges, and , separated by a distance, , is given
<em>k</em> is a constant.
For the charge Z to be at equilibrium, the force exerted on it by charge X must be equal and opposite to the force exerted on it by charge Y.
It is to be placed along the <em>x</em>-axis. Hence, it is on the same line as charges X and Y.
Let the charge on Z be <em>Q</em>. It is positive.
Let the distance from charge X be <em>x m.</em> Then the distance from charge Y will be (0.60 - <em>x</em>) m.
Force due to charge X
Force due to charge Y
Since both forces are equal and opposite,
Applying the quadratic formula,
or
Charge Z can be placed at <em>x</em> = -2.7 m or at <em>x</em> = 0.27 m