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Burka [1]
4 years ago
13

When a positively charged conductor touches a neutral conductor, the neutral conductor will:

Physics
1 answer:
frutty [35]4 years ago
6 0

Answer:

Lose electrons

Explanation:

When a positively charged conductor touches a neutral conductor, the neutral conductor will lose electrons. Only electrons can move from one conductor to another, so if the neutral conductor ended up with a positive charge it means it lost electrons. The conductor touching and the neutral conductor both end up being charged positively.

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QUICK ITS DUE IN 6 MINUTES. create a scenario that applies the 3 laws of motion. Explain in complete sentences how each law if d
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Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

5 0
3 years ago
Please I need help on Physics ASAP!!!
Dafna11 [192]

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you cant cheat on test

Explanation:

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7 0
3 years ago
“Is it correct to say that a radio wave can be considered a low-frequency light wave?
klio [65]

It's weird but technically correct to say that a radio wave can be considered a low-frequency light wave.  Radio and light are both electromagnetic waves.  The only difference is that radio waves have much much much longer wavelengths, and much much much lower frequencies, than light waves have.  But they're both the same physical phenomenon.

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4 0
4 years ago
Determine the 3 standing waves for a 4 m length of rope.
strojnjashka [21]

Harmonics, Loop and Harmonic number

Hope this helps :)

7 0
3 years ago
An object is attached to a hanging unstretched, ideal and massless spring and slowly lowered to its equilibrium position, a dist
Ad libitum [116K]

Answer:

10.6cm

Explanation:

We are given 5.3cm below the starting point (spring extension).

Therefore, to find static vertical equilibrium, we use the equation:

kx = mg

Where:

k = spring constant =

=mg/5.3 kg/s²

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mgx = ½kx²

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To find x, we make x subject of the formula.

Therefore, we have:

x = 2mg/k (after rearranging the equation above)

x = (2mg) / (mg/5.3)

x = 10.6cm

3 0
3 years ago
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