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r-ruslan [8.4K]
3 years ago
11

Which medium below conducts sound the fastest?

Physics
2 answers:
kumpel [21]3 years ago
4 0

Which medium below conducts sound the fastest?

A. a wall

<u>B. Steel </u>

C. Plastic

D. Cardboard​

Karo-lina-s [1.5K]3 years ago
4 0
B. STEEL

Is the answer

Have a nice day <3
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Gamma ray technology can be used to do which of the following?
Rudiy27

Answer:

b

Explanation:

radiation can treat tumors.

5 0
3 years ago
A hot air balloon lifts 50 meters vertically into the air and then comes back down. What are the displacement and distance of th
Marysya12 [62]

Given that a hot air balloon lifts 50 meters vertically into the air and then comes back down.

The displacement is the distance covered in a specific direction.

When the balloon is going up, the displacement is positive. and when the balloon is coming down, the displacement is negative.

The total displacement = 50 - 50 = 0

The distance is a measurement of length between to different points or position.

For distance, there is no need to consider direction. There is no consideration for positive or negative signs

While the distance = 50 + 50 = 100 meters

Therefore, the correct answer is C

That is, The displacement is zero and the distance is 100 meters

Learn more on ; brainly.com/question/24662122

4 0
2 years ago
Read 2 more answers
A spaceship moves radially away from Earth with acceleration 29.4 m/s 2 (about 3g). How much time does it take for sodium street
Gemiola [76]

Answer:

doppler shift's formula for source and receiver moving away from each other:

<em>λ'=λ°√(1+β/1-β)</em>

Explanation:

acceleration of spaceship=α=29.4m/s²

wavelength of sodium lamp=λ°=589nm

as the spaceship is moving away from earth so wavelength of earth should increase w.r.t increasing speed until it vanishes at λ'=700nm

using doppler shift's formula:

<em>λ'=λ°√(1+β/1-β)</em>

putting the values:

700nm=589nm√(1+β/1-β)

after simplifying:

<em>β=0.17</em>

by this we can say that speed at that time is: v=0.17c

to calculate velocity at an acceleration of a=29.4m/s²

we suppose that spaceship started from rest so,

<em>v=v₀+at</em>

where v₀=0

so<em> v=at</em>

as we want to calculate t so:-

<em>t=v/a</em>                                                v=0.17c      ,c=3x10⁸           ,a=29.4m/s²

putting values:

=0.17(3x10⁸m/s)/29.4m/s²

<em>t=1.73x10⁶</em>

7 0
3 years ago
If an object is moving up, is it considered to have a positive or negative velocity?
grin007 [14]

Answer:

A positive velocity

Explanation:

7 0
3 years ago
Una partícula se mueve en el plano XY efectúa un desplazamiento mientras actúa sobre ella una fuerza constante. X= (4i + 3j) m,
dsp73

Answer:

a) La magnitud del desplazamiento es de 5 m

La magnitud de la fuerza es 20 N

b) El trabajo realizado por la fuerza es de 100 J

c) El ángulo entre la fuerza y el plano es 0 °

Explanation:

a) La magnitud del desplazamiento se encuentra por la relación;

\left | X \right | = \sqrt{X_{x}^{2}+X_{y}^{2}}

Lo que da;

\left | X \right | = \sqrt{4^{2}+3^{2}} = 5 \ m

De manera similar, la magnitud de la fuerza, F, se encuentra como sigue;

\left | F \right | = \sqrt{F_{x}^{2}+F_{y}^{2}}

Lo que da;

\left | F \right | = \sqrt{16^{2}+12^{2}} = 20 \ N

b) El trabajo, W, realizado por la fuerza = Fuerza, F × Distancia, X

∴ Ancho = 20 N × 5 m = 100 N · m = 100 J

c) La dirección de la fuerza viene dada por la siguiente fórmula;

tan^{-1} \left (\dfrac{F_y}{F_x} \right ) = tan^{-1} \left (\dfrac{12}{16} \right )  = 38.9^{\circ}

La dirección del plano viene dada por la siguiente fórmula;

tan^{-1} \left (\dfrac{X_y}{X_x} \right ) = tan^{-1} \left (\dfrac{3}{4} \right )  = 38.9^{\circ}

Por tanto, el ángulo entre la fuerza y el plano = 0 °

La fuerza actúa a lo largo del plano.

6 0
3 years ago
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