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3 years ago

What is the basic building block of all matter

Physics

2 answers:

Natalka [10]3 years ago

7 0

I think that is atom.

Igoryamba3 years ago

6 0

An Atom is correct hope u pass your class

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What major region does this profile most likely represent?

alexdok [17]

Answer:

A mid ocean ridge possibly a plate margin spreading area

Explanation:

6 0

3 years ago

How far will a freely falling object fall from rest in 5 seconds?

Travka [436]

<h2>how far will a freely falling object fall from rest in 5 seconds?</h2>

If an object free falls from rest for 5 seconds, its speed will be about 50 m/s.

hope it helps

#carry on learning

3 0

3 years ago

An object is released from rest and falls a distance h during the first second of time. How far will it fall during the next sec

Viefleur [7K]

Answer:

E. 3h

Explanation:

We know that

u = 0 m/s.

velocity after t = 1s

v = u+gt = 0+9.81 x 1s= 9.81 m/s

distance covered in 1st sec

= =>> ut+0.5 x g x t²

=>>0 + 0.5x 9.81 x 1 = 4.90m

Let 4.90 be h

distance travelled in 2nd second will now be used

So velocity after t = 1s

=>>1 x t+ 0.5 x g x t²

=>9.81x 1 + 0.5 x 9.81 x 1 = 3 x 4.90

So since h= 4.90

Then the ans is 3x h = 3h

3 0

3 years ago

The earth remains in orbit around the sun due to the force of gravity. How does the force of gravity exerted by the sun on the e

Katen [24]

The sun is bigger than the earth, therefore it has more gravitational force than the earth.

4 0

3 years ago

Read 2 more answers

The magnitude of the magnetic flux through the surface of a circular plate is 6.80 10-5 T · m2 when it is placed in a region of

PIT_PIT [208]

Answer:

B = 4.1*10^-3 T = 4.1mT

Explanation:

In order to calculate the strength of the magnetic field, you use the following formula for the magnetic flux trough a surface:

$\Phi_B=S\cdot B=SBcos\alpha$ (1)

ФB: magnetic flux trough the circular surface = 6.80*10^-5 T.m^2

S: surface area of the circular plate = π.r^2

r: radius of the circular plate = 8.50cm = 0.085m

B: magnitude of the magnetic field = ?

α: angle between the direction of the magnetic field and the normal to the surface area of the circular plate = 43.0°

You solve the equation (1) for B, and replace the values of the other parameters:

$B=\frac{\Phi_B}{Scos\alpha}=\frac{6.80*10^{-5}T.m^2}{(\pi (0.085m)^2)cos(43.0\°)}\\\\B=4.1*10^{-3}T=4.1mT$

The strength of the magntetic field is 4.1mT

4 0

3 years ago