Answer:
Half-life for this reaction is 2.56s
Explanation:
The general expression in a reaction that follows first-order is:
Ln[A] = -kt + ln[A]₀
<em>Where [A] is concentration of reactant after time t, </em>
<em>k is rate constant = 0.271s⁻¹</em>
<em>[A]₀ is initial concentration of reactant.</em>
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Half-life is defined as the time required to decrease the initial concentration of the reactant (I2 in this case) halved.
If [A]₀ = 1
[A] = 1/2
Solving the equation:
Ln[1/2] = -0.271s⁻¹*t + ln[1]
Ln[1/2] = -0.271s⁻¹*t + 0
Ln[1/2] = -0.271s⁻¹t
Ln 2 = 0.271s⁻¹
2.56s = t
Half-life for this reaction is 2.56s
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