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3 years ago

Which of the following reactions produce oxygen gas?

1 answer:

5 0

<span>The correct answer is photosynthesis. Photosynthesis is the process in plants to make their food. This involves the use carbon dioxide to react with water and make sugar or glucose as the main product and oxygen as a by-product.</span>

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I REALLY NEED YOUR HELPPPPPP!!!!!!!!!!!!!!!!!!!!when the boy was skating,kinetic energy was ______and thermal energy was _______

77julia77 [94]

Answer:high,low,decreasing,increasing,low,high,potential,kinetic

Explanation:

4 0

3 years ago

If molecule dissociates in water what does it do

natita [175]

It either forms a base or an acid...I think that's the answer you're looking for

4 0

3 years ago

A sample of iron absorbs 67.5 j of heat upon which the temperature of the sample increases from 21.5 °c to 28.5 °c. if the speci

asambeis [7]

Q = mcΔθ

67.5 = m x 0.45 x (28.5 - 21.5)

M = 67.5 / 3.15
= 21.4 g

3 0

3 years ago

Read 2 more answers

Submit What is the solubility of Cd3(POA) 2 in water? (Ksp of Cd3(PO4)2 is 2.5 x 10-33) | 1 2 3 +/- . 0 x100

vesna_86 [32]

<u>Answer:</u> The solubility of $Cd_3(PO_4)_2$ in water is $1.18\times 10^{-7}mol/L$

<u>Explanation:</u>

The balanced equilibrium reaction for the ionization of cadmium phosphate follows:

$Cd_3(PO_4)_2\rightleftharpoons 3Cd^{2+}+2PO_4^{3-}$

3s 2s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Cd^{2+}]^3[PO_4^{3-}]^2$

We are given:

$K_{sp}=2.5\times 10^{-33}$

Putting values in above equation, we get:

$2.5\times 10^{-33}=(3s)^3\times (2s)^2\\\\2.5\times 10^{-33}=108s^5\\\\s=1.18\times 10^{-7}mol/L$

Hence, the solubility of $Cd_3(PO_4)_2$ in water is $1.18\times 10^{-7}mol/L$

6 0

3 years ago

Archy [21]

Answer:

<h3>The answer is option C</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of liquid = 15 mL

density = 2.5 g/mL

We have

mass = 15 × 2.5

We have the final answer as

Hope this helps you

6 0

3 years ago