Answer: d :The blue and orange soccer balls; they have more mass than the black soccer ball, but changed speed by the same amount.
Answer:
Explanation:
2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s); ΔᵣH = ?
The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is
2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s)
ΔfH°/kJ·mol⁻¹: 0 -824.3 -1675.7 0
![\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [1(-1675.7) + 2(0)] - [2(0) - 1(-824.3)]\\& = & -1675.7 + 824.3\\& = & \textbf{-851.4 kJ/mol}\\\end{array}\\\text{The enthalpy change is } \large \boxed{\textbf{-851.4 kJ/mol}}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D%5CDelta_%7B%5Ctext%7Br%7D%7DH%5E%7B%5Ccirc%7D%20%26%20%3D%20%26%20%5B1%28-1675.7%29%20%2B%202%280%29%5D%20-%20%5B2%280%29%20-%201%28-824.3%29%5D%5C%5C%26%20%3D%20%26%20-1675.7%20%2B%20824.3%5C%5C%26%20%3D%20%26%20%5Ctextbf%7B-851.4%20kJ%2Fmol%7D%5C%5C%5Cend%7Barray%7D%5C%5C%5Ctext%7BThe%20enthalpy%20change%20is%20%7D%20%5Clarge%20%5Cboxed%7B%5Ctextbf%7B-851.4%20kJ%2Fmol%7D%7D)
Answer:
2.7 mL
Explanation:
The equation of the reaction is;
2AlBr3 + 3Cl2 -----> 2AlCl3 + 3Br2
Number of moles in 2.12 x 1022 formula units of aluminum bromide
1 mole of AlBr3 = 6.02 * 10^23 formula units
x moles = 2.12 x 1022 formula units
x = 2.12 x 1022 formula units * 1 mole/ 6.02 * 10^23 formula units
x = 0.0352 moles of AlBr3
According to the reaction equation;
2 moles of AlBr3 produces 3 moles of Br2
0.0352 moles of AlBr3 produces 0.0352 moles * 3 moles /2 moles
= 0.0528 moles of Br2
Mass of Br2 produced = 0.0528 moles of Br2 * 159.808 g/mol
Mass of Br2 produced = 8.44g
But density = mass/volume
volume = mass/density
volume of Br2 = 8.44 g/ 3.12 g/mL
volume of Br2 = 2.7 mL
