A conjugate acid is given by the acid-base theory of Bronsted–Lowry. The conjugate acid of a weak base, trimethylamine is ((CH₃)₃NH⁺) trimethylammonium ion.
<h3>What is a conjugate acid?</h3>
A conjugate acid is a compound that has been formed when a base accepts the hydrogen or the proton ion from an acid. It can also be said that a hydrogen ion is added to a base.
The conjugate acid differs from the base by the addition of one proton ion to it. The reaction of a weak base, trimethylamine can be shown as,
(CH₃)₃N(aq) + H₃O⁺(aq) ⇌ (CH₃)₃NH⁺(aq) + H₂O(l)
Here, the trimethylamine compound has accepted a proton from hydronium to produce a conjugate acid, trimethylammonium cation, (CH₃)₃NH⁺.
Therefore, trimethylammonium (CH₃)₃NH⁺ is the conjugate acid of trimethylamine.
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Answer:
See explanation
Explanation:
A carbohydrate is formed from carbon, hydrogen and oxygen. These three elements are combined in every carbohydrate.
Even though carbohydrates are composed of only these three atoms, the number of atoms of these elements in each carbohydrate as well as the spatial arrangement of these atoms in each carbohydrate is not the same.
This means that different carbohydrates contain different number of carbon, oxygen and hydrogen atoms which are arranged in different ways in space. This gives room for the existence of many different types of carbohydrates all consisting of carbon, hydrogen and oxygen atoms.
Answer:
Option A. 2, 3, 2
Explanation:
We'll begin by balancing the equation. This can be achieved by doing the following:
Fe + Cl2 —> FeCl3
There are 2 atoms of Cl on the left side and 3 atoms on the right side. It can be balance by putting 3 in front of Cl2 and 2 in front of FeCl3 as shown below:
Fe + 3Cl2 —> 2FeCl3
There are 2 atoms of Fe on the right side and 1 atom on the left side. It can be balance by putting 2 in front of Fe as shown below:
2Fe + 3Cl2 —> 2FeCl3
Now the equation is balanced.
The coefficients are : 2, 3, 2
I think the correct answer from the choices listed above is option A. <span>In an exothermic reaction, the bonding energy of the product is </span><span>less than the reactant because it is only at this condition that the energy is released by the reaction.</span>
Answer:
(a) 
(b) 
(c) 
Explanation:
Hello,
(a) In this case, since entropy remains unchanged, the constant 
should be computed for air as an ideal gas by:
Next, we compute the final temperature:
Thus, the work is computed by:
(b) In this case, since 
is given, we compute the final temperature as well:
And the isentropic work:
(c) Finally, for isothermal, final temperature is not required as it could be computed as:
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