Question

A 16.0 16.0 L sample of neon gas has a pressure of 23.0 23.0 atm at a certain temperature. At the same temperature, what volume would this gas occupy at a pressure of 1.50 1.50 atm? Assume ideal behavior. V = V= L

Answer 1

Answer: 245 L

Explanation:-

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=23.0atm\\V_1=16.0L\\P_2=1.50atm\\V_2=?$

Putting values in above equation, we get:

$23.0\times 16.0=1.50\times V_2\\\\V_2=245L$

Thus new volume of gas is 245 L