Answer:
I speak English can someone translate
Explanation:
Answer:
<em>option</em><em> </em><em>C </em><em>5</em>
<em>hope </em><em>this</em><em> answer</em><em> helps</em><em> you</em><em> dear</em><em>!</em><em> </em><em>take </em><em>care</em>
Answer:
28.75211 kj
Explanation:
Given data:
Mass of iron bar = 841 g
Initial temperature = 84°C
Final temperature = 7°C
Heat released = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
specific heat capacity of iron is 0.444 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 7°C - 84°C
ΔT = -77°C
By putting values,
Q = 841 g × 0.444 j/g.°C × -77°C
Q = 28752.11 j
In Kj:
28752.11 j × 1 kJ / 1000 J
28.75211 kj
Answer:
7.508 Moles Vangkee
Explanation:
semoga membantu ya vangkee
