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Art [367]
3 years ago
14

Why isn't the Liter a basic SI unit of measurement? (In your answer use at least one SI base unit of measurement and one other d

erived unit of measurement to support your answer.) *
Chemistry
1 answer:
Y_Kistochka [10]3 years ago
5 0

Answer:

What give me a few minutes I have to finish my test them I will answer in comments.

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How much energy does it take to melt 2 kg of ice? (Refer to table of<br> constants for water.)
ioda
It would be C

2 kg x 1000 g/kg x 1mol/18.02 x 6.03 kj/mol = 669kj


5 0
3 years ago
Read 2 more answers
The nucleus of the atom is held together by the attraction of the positively charged protons and the negatively charged electron
7nadin3 [17]
False.........................
8 0
3 years ago
If the pressure changes from 1 atm to 3 atm, what does the volume of 30 L change to
DiKsa [7]

Answer: 10L

Explanation:

Given that:

Initial pressure P1 = 1 atm

New pressure P2 = 3 atm

Initial volume V2 = 30 L

New volume V2 = ?

Since pressure and volume are involved, apply the formula for Boyle's law

P1V1 = P2V2

1 atm x 30L = 3 atm x V2

30 atm L = 3 atm x V2

V2 = (30 atm L / 3 atm)

V2 = 10L

Thus, volume changed to 10 liters

5 0
3 years ago
How can you tell if glucose is present?
rosijanka [135]

Answer:

Plants use photosynthesis to make glucose. Glucose is also know as sugar. You can tell it is present if the plant receives sunlight as well as water.

Explanation:

MARK BRAINLIEST

4 0
3 years ago
The graph given below shows the motion of four runners P, Q, R, and S in a 5 km marathon.
wel

Answer:-

As we can see from the graphical data,

The distance covered by all the four runners is the same 5 km.

Among the four athletes, Athlete P covers the distance in under three hours.

It is the minimum time taken among the four athletes.

Thus Athlete P covers the 5 km distance in the minimum amount of time.

We know that speed = \frac{Distance}{Time}

Since time taken for P is minimum, his speed is the maximum. P ran the fastest.

Time taken by Q = 4.5 hours.

Speed of Q = \frac{Distance}{Time taken by Q}

                     = \frac{5km}{4.5hour}

                    = 1.1 km/ hr

Time taken by R = 6 hours.

Speed of R = \frac{Distance}{Time taken by R}

                     = \frac{5km}{6hour}

                    = 0.8 km/ hr

3 0
3 years ago
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