Since there is no weight, I would assume that this is a 100g of pure compound.
Okay so I would be changing the percentage to gram to solve for the mole.
So
40.0g C (1 mol C/12.01 g C) = 3.33 mol C
6.73g H (1 mol H/1.01 g H ) = 6.66 mol H
53.3g O (1 mol O/16.00 g O) = 3.33 mol O
With that, two of our moles is 3.33, so we consider that are our 1, as it is also the lowest. Therefore the empirical formula is CH2O
Answer:
It is <u>KEPLER</u>
Explanation:
Kepler defined the sun's orbit.
okay.
Your answer is probably
Vaporization point
At constant temperature and pressure, the change in Gibbs free energy is defined as DG= DH-TDS hope this helps bb ♡
I just took the test it is A hope this helps :)
