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Alja [10]
3 years ago
9

I need help with this question

Mathematics
1 answer:
vladimir1956 [14]3 years ago
7 0
(a) is 32x-12
(b) is 22y
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Interior and Exterior Triangle Angles (0/5)
sweet-ann [11.9K]

Answer:

<h3>      ∠R = 69</h3>

Step-by-step explanation:

<h2>Angle sum property</h2>

Sum of all angles of triangle = 180

     5x - 11 + 3x - 3 + 3x + 18 = 180

      5x + 3x + 3x  -11 - 3 + 18 = 180

Combine like terms

                             11x  + 4 = 180

                                   11x = 180 - 4

                                   11x = 176

                                      x = 176/11

                                       x = 16

∠R = 5x - 11

   = 5*16 - 11

   = 80 - 11

    = 69

8 0
2 years ago
Factor w^2-7w-8 show work
svlad2 [7]
Find what 2 numbers add to -7 and multiply to -8
+1 and -8
(w+1)(w-8)
7 0
3 years ago
Round 249798.828806 to the nearest ten.
Artyom0805 [142]
249798.8

The nearest ten
5 0
2 years ago
Read 2 more answers
Number 2 is what I'm stuck on
DENIUS [597]
Let's say that ground level is 0. When she goes down to the basement, she is going -12 feet since each flight of stairs is12 feet. Then she goes up 12 more feet= -12+12=0. She is back at ground level. Then she goes up another 12 feet= 0+12= 12. So I believe the answer is 12 feet.
5 0
3 years ago
Find the measurements (the length L and the width W) of an inscribed rectangle under the line with the 1st quadrant of the x &am
Leni [432]

The question is incomplete. Here is the complete question.

Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -\frac{3}{4}x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.

Answer: L = 1; W = 9/4; A = 2.25;

Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:

A = x.y

A = x(-\frac{3}{4}.x + 3)

A = -\frac{3}{4}.x^{2}  + 3x

To maximize, we have to differentiate the equation:

\frac{dA}{dx} = \frac{d}{dx}(-\frac{3}{4}.x^{2}  + 3x)

\frac{dA}{dx} = -3x + 3

The critical point is:

\frac{dA}{dx} = 0

-3x + 3 = 0

x = 1

Substituing:

y = -\frac{3}{4}x + 3

y = -\frac{3}{4}.1 + 3

y = 9/4

So, the measurements are x = L = 1 and y = W = 9/4

The maximum area is:

A = 1 . 9/4

A = 9/4

A = 2.25

6 0
3 years ago
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