Answer: There are 6.9 mol of
are required to react completely with 2.30 mol of S.
Explanation:
The given reaction equation is as follows.

Here, 1 mole of S is reaction with 3 moles of
which means 1 mole of S requires 3 moles of
.
Therefore, moles of
required to react completely with 2.30 moles S are calculated as follows.

Thus, we can conclude that there are 6.9 mol of
are required to react completely with 2.30 mol of S.
The experimental control is the standard used as a comparison for the experimental groups.
For example, you may be trying to find out how different types of disinfectants affect bacterial growth. The control group would receive <em>no</em> disinfectant whereas the experimental groups would be the ones on which the disinfectants were tested.
Hope this makes sense!
Given mass of tungsten, W = 415 g
Molar mass of tungsten, W = 183.85 g/mol
Calculating moles of tungsten from mass and molar mass:

The number of molecules that are in balloon are = 2.227 x10^23 molecules
<h3> calculation</h3>
calculate the number of moles of NO
moles = mass/molar mass
molar mass of NO = 14+ 16 = 30 g/mol
moles is therefore= 11.1 g/30g/mol= 0.37 moles
by use of Avogadro's constant that is
1 mole= 6.02 x10^23 molecules
0.37 =? molecules
=(6.02 x10^23 x 0.37 moles)/ 1mole=2.227 x10^23 molecules
Roughness of the surface and weight of the object.