Answer:
Explanation:
Ratio of mass of C , N , H and O
= .8007 :0.9333:0.2016:2.133
Ratio of moles of C , N , H and O
= .8007/12 : .9333 / 14 : 0.2016 / 1 : 2.133/16
= .0667 : .0667: .2016 : .1333
= .0667 / .0667 : .0667 / .0667 : .2016 /.0667 : .1333 / .0667
= 1 : 1 : 3: 2
Hence empirical formula = CNH₃O₂
7 .
Weight of titanium Ti = 1.916 g
Weight of oxygen = 3.196 - 1.916 = 1.28 g
Ratio of weight of Ti and O
= 1.916 : 1.28
Ratio of moles of Ti and O
1.916/48 : 1.28/16 [ Molecular weight of Titanium is 48 ]
= .04 : .08
= .04/.04 : .08/.04
= 1 :2 .
Empirical formula
TiO₂
