Ask question

Ask question

All categories

1 year ago

15

A 0. 25-kg toy car experiences a net force of 9. 0 n while slowing down to a complete stop. What is the magnitude of its acceler

ation?.

1 answer:

mezya [45]1 year ago

6 0

Answer:

a = 36 m/s

Explanation:

Given:

F = 9 N

m = 0.25 kg

a= ?

Use the equation:

F = ma (divide by m on both sides to get a alone)

a = F/m= 9/0.25 = 36 m/s

You might be interested in

I need help by today guys plz help

NISA [10]

radio waves bc they have the longest wave lenthgs in a magnetic spectrum

5 0

3 years ago

The best way to cool soft and thick foods (such as beans, sauce or chili) when using the refrigerator is?

AnnZ [28]

<span>The best way to cool soft and thick foods when using the refrigerator is by having them to be placed and poured on a pan or another way is by having them to be placed in one container in which they are in a water bath, to be heated of.</span>

3 0

3 years ago

Read 2 more answers

falling objects drop with an average acceleration of 9.8m/sec/sec. if an object falls from a tall building how long will it take

sveta [45]

Answer:

5 seconds

Explanation:

<em>Acceleration = (final velocity - initial velocity) ÷ time</em>

<em> $a = \frac{v - u}{t}$ </em>

<em> $9.8 = \frac{49 - 0}{t}$ </em>

<em> $9.8 = \frac{49}{t}$ </em>

<em> $9.8t = 49$ </em>

<em> $t = \frac{49}{9.8}$ </em>

<em> $t = 5$ </em>

8 0

3 years ago

A girl is standing 150m in front of a tall building, fires a shot with starting pistol. A boy standing 350m behind her, hears tw

Natasha2012 [34]

Answer:

300 m/s

Explanation:

The difference in time between the two bangs is 1 s.

Thus;

t2 - t1 = 1

We know that distance/time = speed.

Thus;

d2/v - d1/v = 1

Multiply through by v to get;

d2 - d1 = v

Where v is speed of sound in air.

d1 = 350 m

d2 = (150 × 2) + 350 = 650 m

Thus;

v = d2 - d1 = 650 - 350 = 300 m/s

8 0

3 years ago

A closed-end organ pipe is used to produce a mixture of sounds. The third and fifth harmonics in the mixture have frequencies of

nexus9112 [7]

Answer:

$F_1=366.67Hz$

Explanation:

From the question we are told that:

Frequency of 3rd harmonics $F_3=1100$

Frequency of 5th harmonics $F_3=1833$

Generally the equation for Wavelength at 3rd Harmonics is mathematically given by

$\lambda_3=\frac{4}{3}l$

Therefore

$F_3=\frac{3v}{4l}$

Generally the equation for Wavelength at 1st Harmonics is mathematically given by

$\lambda_1=\frac{4}{1}l$

Therefore

$F_1=\frac{v}{4l}$

Generally the equation for the frequency of the first harmonic is mathematically given by

$F_1=\frac{F_3}{3}$

$F_1=\frac{1100}{3}$

$F_1=366.67Hz$

7 0

3 years ago