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Juliette [100K]
3 years ago
6

Geometry problem below

Mathematics
2 answers:
AVprozaik [17]3 years ago
6 0

Answer:

Answer D. "ASA"

Step-by-step explanation:


Orlov [11]3 years ago
3 0

Answer:

ASA

Step-by-step explanation:

When looking at the postulates, we need to know what they stand for

SSS, is side side side

SAS is Side angle side

AAS is angle angle side

ASA is Angle side angle  (the side is between the angles)


In the picture we know 2 angles and the included side

so we will use ASA

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Y=-1/2x +7
yarga [219]

Answer:

B; (2,-4)

Step-by-step explanation:

The general equation of a straight line is;

y = mx + b

where m is the slope and b is the y-intercept

So from the question, when we look at the given equation, its slope is -1/2

mathematically, when two lines are perpendicular, the product of their slopes is -1

thus;

m1 * m2 = -1

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m2 = 2

The general equation form is;

y-y1 = m(x-x1)

where (x1,y1) = (4,0)

y-0 = 2(x-4)

y = 2x - 8

So, now we look at the point that will work for this equation

For the line that will work, if we substitute its x-value, we get the y-value

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4 0
3 years ago
Lim t^4 - 6 / 2t^2 - 3t + 7
Harman [31]

I think you meant to say

\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}

(as opposed to <em>x</em> approaching 2)

Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}

6 0
3 years ago
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