You randomly select one card from a 52-card deck. Find the probability of selecting a black six or a black eight.

1 answer:

7 0

Since there are 2 black sixes and 2 black eights in a typical deck of 52 cards, the probability of choosing one of those 4 out of 52 is 4/52 or 1/13.

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In What quadrant is the point (-5, -5) located

sineoko [7]

Answer:

Since both values are negative, it can be found in the 3rd quadrant

<em>Feel free to mark this as brainliest :D</em>

4 0

3 years ago

Michael recorded the number of points his team scores for the first seven basketball games 64 5860 5256 62-54 which box plot cor

natka813 [3]

The correct option is fourth option

Explanations:

From the data, re-arranging in ascending order, the median of the data is 58.

The upper quartile is 62, while the lower quartile is 54

From the options, only the 4th options represent a box plot of median 58, upper quartile of 62 and lower quartile of 54. This makes it the correct option

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1 year ago

you work at a hair salon and get left a 35 tip on a 112 haircut and color service . What percent tip did your customer give you

levacccp [35]

31.25 percent of 112 is 35

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3 years ago

HELP ME PLEASE I NEED THIS LOVE U GUYS <33

Sedaia [141]

Answer:

$\huge\boxed{\sf Volume = 384 \ cm^3}$

Step-by-step explanation:

Slant Height = 10 cm

Base Edge = 12 cm

<u>Finding the Height using Pythagorean Theorem:</u>

$\sf c^2 = a^2 + b^2 \\\\Where \ c = 10\ cm , b = 6\ cm [Half of 12] \ and \ a \ is \ height\\\\10^2 = a^2 + 6^2\\\\100=a^2 +36\\\\100-36 = a^2\\\\64 = a^2\\\\Taking \ sqrt \ on \ both \ sides\\\\Height= 8 \ cm$

$\rule[225]{225}{2}$

<u>Now, Finding the volume:</u>

$\sf Volume = a^2 \frac{h}{3}\\\\ Where \ a \ is base \ edge \ and \ h \ is \ height\\\\Volume = (12)^2 \frac{8}{3} \\\\Volume = 144 \frac{8}{3} \\\\Volume = 48*8\\\\\bold{Volume = 384 \ c m^3}$