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makkiz [27]
3 years ago
10

What is the effect of changing the wire in a circuit from a straight thick wire to a straight thin wire?

Physics
1 answer:
Murrr4er [49]3 years ago
3 0
Its letter B, im pretty sure
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_____ have a nearly circular orbit.
WITCHER [35]

The question is poor.

It expects you to choose 'B', but things aren't nearly that simple.

We picture all of the asteroids bunched up in a neat bunch between
the orbits of Mars and Jupiter, with each asteroid following its own
nearly circular orbit.  But many asteroids have wildly non-circular
'eccentric' orbits, sometimes being closer to the sun than the Earth is. 
You know how you hear so much discussion about when did the Earth
get hit by an asteroid ? and when will the Earth be hit by another asteroid ?
and what will happen when the Earth is hit by an asteroid again ?  None
of that would be possible if asteroids all had nearly circular orbits.

We picture comets as having these loooong skinny orbits, spending
most of every orbit waaay out in the solar system, and then dipping
close to the sun for a few days, and then going back waaaay out again. 
But there are also many comets in nearly circular orbits around the sun. 
You never hear anything about them, because you can never see them
without a powerful telescope, and they never do anything exciting. 
So some comets could be a correct answer to this question too.

And since meteoroids are the remains of old comets, and follow the
orbit of the comet that they chipped off from, there are a lot of meteoroids
in circular orbits too, and they could also be a correct answer to this question.

8 0
4 years ago
A copper transmission cable 140 {\rm km} long and 12.5 {\rm cm} in diameter carries a current of 115 {\rm A}.
SpyIntel [72]

Answer:

1. V=22.0407\ V

2. Q=9126837\ J

Explanation:

Given:

length of copper cable, l=140\ km=1.4\times 10^5\ m

diameter of copper cable, d=12.5\ cm=0.125\ m

current through the copper wire, i=115\ A

We have the resistivity of copper, \rho=1.68\times10^{-8}\ \Omega.m

<u>We know that the resistance of a wire is given as:</u>

R=\rho.\frac{l}{a}

where:

a= cross sectional area of the wire

R=1.68\times 10^{-8}\times\frac{140000}{\pi.\frac{0.125^2}{4} }

R=0.1917\ \Omega

1.

<u>Now from the  Ohm's law:</u>

V=R.i

V=0.1917\times 115

V=22.0407\ V

2.

<u>From the Joules law the thermal energy generated as an effect of electrical energy is mathematically given as:</u>

<u />Q=i^2.R.t

where:

t= time duration for which the current flows

Q=115^2\times 0.1917\times 3600 (∵ we have 3600 seconds in 1 hour)

Q=9126837\ J

5 0
3 years ago
Electromagnetic waves are used extensively in modern technology. Many devices are built to emit and/or receive EM waves at a ver
il63 [147K]

Answer: Option D and E

Explanation: Across the electromagnet spectrum, the frequency increases but the wavelength reduces.

This implies that radio waves have the longest wavelength but the smallest frequency, while gamma rays have the shortest wavelength but the highest frequency.

This implies that there is an inverse relationship between wavelength and frequency.

Of all the technologies listed above, wireless internet has the highest frequency hence making it have the shortest wavelength.

Also by comparing values from the data given to us above, it is possible for some wireless internet device to operate within the same frequency range of the microwave.

3 0
3 years ago
1.When molecules change state of matter from a liquid to a solid, then _______________.
Jet001 [13]
The answwr would be d and c becasuase it just would 
4 0
3 years ago
Read 2 more answers
Given a double slit apparatus with slit distance 2 mm, what is the theoretical maximum number of bright spots that I would see w
katen-ka-za [31]

Answer:

The values is  m_{max} = 8001 \  bright \ spots

Explanation:

From the question we are told that

    The slit distance is  d  =  2 \ mm  =  2*10^{-3} \ m

    The  wavelength is  \lambda =  500 \ nm =  500 *10^{-9} \ m

At the first half of the screen from the central maxima

   The number of bright spot according to the condition for constructive interference is  

          n  =  \frac{d *  sin (\theta )}{\lambda}

For maximum number of spot \theta =  90^o

So  

       n  =  \frac{2*10^{-3} *  sin (90 )}{500 *10^{-9}}

        n  =4000

Now for the both sides plus the central maxima  we have

      m_{max} = 2 * n  + 1

substituting values

       m_{max} = 2 *  4000 + 1

       m_{max} = 8001 \  bright \ spots

   

6 0
4 years ago
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