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3 years ago

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If u = 5 inches, v = 7 inches, w = 2 inches, x = 6 inches, y = 12 inches, and z = 3 inches, then what is the perimeter of the ob

ject

1 answer:

m_a_m_a [10]3 years ago

5 0

The answers because you have to add all of them together 35

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A blind taste test will be conducted with 9 volunteers to determine whether people can taste a difference between bottled water

Aloiza [94]

Answer:

The answer is $\frac{1}{256}$

Step-by-step explanation:

If we assume that people cannot taste a difference between bottled water, then the probability of identifying tap water is 0.5

Thus, P(identify tap water)=0.5

The probability that at least 8 of the 9 people identify the tap water correctly is the sum of the probabilities

8 of 9 people identified correctly or
9 of 9 people identified correctly

Since P(identify tap water)=0.5 each probabilities are the same and equal to

$0.5^9$ = $\frac{1}{512}$

So we have $2*\frac{1}{512}$ = $\frac{1}{256}$

6 0

3 years ago

The volumes of two cylindrical cans of the same shape vary directly as the cubes of their radii. If a can with a six-inch radius

Cerrena [4.2K]

Answer:

The second similar can with a radius of 24-inch radius will hold 12 gallons

Step-by-step explanation:

The given parameters are;

The volumes of the cylindrical can ∝ (The radius of the cans)³

The volume of first can, V₁ = 1¹/₂ pints

The radius of the first can, r₁ = 6-inch

The radius of the second can, r₂ = 24-inch

Therefore, we have;

V ∝ r³

V = k × r³

∴ 1¹/₂ pints ∝ (6 in.)³

1¹/₂ pints = 43.3125 in³

∴ 43.3125 in³ = k × 216 in.³

The constant of proportionality, k = 43.3125/216 = 0.2005208333

Therefore, we have for the second can, we have;

V₂ = k × r₂³ = 43.3125/216 × (24 in.)³ = 2772 in.³

The volume of the second can = 2772 in.³

1 in.³ = 0.004329 gallons

∴ 2772 in.³ = 2772 × 0.004329 gallons = 12 gallons

Therefore, the volume the second similar can with a 24-inch radius will hold = 12 gallons.

8 0

3 years ago

Which is the best summary of this part of the passage?

nignag [31]

Answer: d

hahehebbsjdhdbrbsndjjd

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the sum of the first one hundred positive integers. see fig 6.26

nignag [31]

Here's a pattern to consider:
1+100=101
2+99=101
3+98=101
4+97=101
5+96=101
.....
This question relates to the discovery of Gauss, a mathematician. He found out that if you split 100 from 1-50 and 51-100, you could add them from each end to get a sum of 101. As there are 50 sets of addition, then the total is 50×101=5050
So, the sum of the first 100 positive integers is 5050.

Quick note
We can use a formula to find out the sum of an arithmetic series:
$s = \frac{n(n + 1)}{2}$
Where s is the sum of the series and n is the number of terms in the series. It works for the above problem.

8 0

3 years ago

How do u do this question?

goldenfox [79]

A --------¢ D

B --------¢ E

C --------¢ F

Just match like this buddy.

6 0

3 years ago