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torisob [31]
3 years ago
12

If u = 5 inches, v = 7 inches, w = 2 inches, x = 6 inches, y = 12 inches, and z = 3 inches, then what is the perimeter of the ob

ject
Mathematics
1 answer:
m_a_m_a [10]3 years ago
5 0
The answers because you have to add all of them together 35
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What is the name of the number that tells you how many groups?
OLga [1]

Answer:

Love u man :) can i get crown please

Step-by-step explanation:

you begin with fifteen items and want to know how many groups you can make with three items in each group. The answer, or quotient, is the number of groups. 3 = 5. The number that is divided is called the dividend and the number which the dividend is being divided by is the divisor.

6 0
3 years ago
FIND THE VOLUME OF A PRISM-SHAPED WATERMELON IN CUBIC INCHES IF ITS LENGTH IS 10 INCHES ITS WIDTH IS 2/3 FOOT AND ITS HIEGHT IS
svetlana [45]
The way to find Volume is V=lwh so plug in the length, width and height( V=(10)x(2/3)x(9) ) and you'll get your answer.
4 0
3 years ago
What's the range of the function shown below ? Thanks
Artemon [7]
Y>0 because raising a number to a negative power doesn't make it negative
5 0
3 years ago
Solve for x <br> •26.45 <br> •10.93<br> •14.26<br> •22.19 <br> •20.26
ollegr [7]

Answer:

x = 26.45

Step-by-step explanation:

Cos theta = adjacent side / hypotenuse

cos 50 = 17 /x

Switch the x and the cos 50

x = 17 / cos 50

x =26.44730506

Rounding to 2 decimal places

x = 26.45

8 0
3 years ago
What is the inverse function of f(x) = 25x-3?
Harrizon [31]

Answer:

The answer is

<h2>{f}^{ - 1} (x) =  \frac{x +3 }{25}</h2>

Step-by-step explanation:

f(x) = 25x - 3

To find the inverse of f(x) , equate f(x) to y

That's

y = f(x)

We have

y = 25x - 3

Next interchange the terms that's x becomes y and y becomes x

x = 25y - 3

<u>Next solve for y</u>

Move 3 to the other side of the equation

That's

25y = x +  3

<u>Divide both sides by 25</u>

\frac{25y}{25}  =  \frac{x + 3}{25}

We have the final answer as

{f}^{ - 1} (x) =  \frac{x +3 }{25}

Hope this helps you

5 0
3 years ago
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