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torisob [31]
3 years ago
12

If u = 5 inches, v = 7 inches, w = 2 inches, x = 6 inches, y = 12 inches, and z = 3 inches, then what is the perimeter of the ob

ject
Mathematics
1 answer:
m_a_m_a [10]3 years ago
5 0
The answers because you have to add all of them together 35
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Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.

\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill

\begin{cases} h=0\\ k=0\\ a=2\\ c=4 \end{cases}\implies \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{b^2} \\\\\\ c^2=a^2+b^2\implies 4^2=2^2+b^2\implies 16=4+b^2\implies \underline{12=b^2} \\\\\\ \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{12}\implies \boxed{\cfrac{x^2}{4}-\cfrac{y^2}{12}}

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If f(x)=2x+5, then f(4) represents what
RSB [31]
<span>f(x)=2x+5
then
</span><span>f(4)=2(4) +5 = 8 + 5 = 13

hope it helps</span>
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